Latest Elitmus Aptitude Question SOLUTION: if the sides of a hexagon are in AP and the last most sides give an average of 160 degree then what is the average of the least most sides?

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(#M40165281) ELITMUS Numerical Ability question AP Keep an EYE

if the sides of a hexagon are in AP and the last most sides give an average of 160 degree then what is the average of the least most sides?

Asked In Elitmus ujala jha (6 years ago)

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Devendra Marghade  (6 years ago)

80 degree

Sum of the interior angles of a hexagon is 720°.
As the sides of hexagon are in AP, then its interior angles will also be in AP.
Given, last most side has 160° and let least most side has angle of a° and difference between each angle=d° with number of sides n=6, then 160=a+(n-1)d
Also sum of an AP, Sn=(n/2)[2a+(n-1)d]=(n/2)[a+a+(n-1)d]
=> 720=3(a+160)
=> a=80

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Rajneesh  (4 years ago)

Answer=80 degree

Sum of the interior angles of a hexagon is 720°.
As the sides of hexagon are in AP, then its interior angles will also be in AP.
So angle of triangle are a-3d, a-2d,a-d,a+d,a+2d,a+3d
Sum of all interior angle of hexagon is 720.
a-3d+ a-2d+a-d+a+d+a+2d+a+3d=720
6a=720
a=120
last most side a+3d=160
3d=40
least most side a-3d=120-40=80

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Gayatri Rao  (6 years ago)

how 80 has come plz explain

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Ashwini Nandan  (4 years ago)

sum of interior angles=720.
ap and 6 sides given so sides will be a,a+d,a+2d,a+3d,a+4d,a+5d.
therefore,a+5d=160(given).
and sum of all sides that is,6a+15d=720.
using these2 equations we get the smallest side that is a=80.

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