Latest TCS Aptitude Question SOLUTION: In how many possible ways can you write 3240 as a product of 3 positive integers a, b and c.

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In how many possible ways can you write 3240 as a product of 3 positive integers a, b and c.

Asked In TCS anuja hore (5 years ago)

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kunal  (5 years ago)

COULD U EXPLAIN KAUSHIK HOW YOU SOLVE THAT

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Sreenivas  (5 years ago)

Make the given number as prime factors.,(Ex:3240 as
324*10
2*162 5*2(for 10)
2*81
3*3*3*3
so total 2^3 3^4 5^1
we have formula. That is (n+r-1)C(r-1)
where n is power and r is no.of positive integers
by that, for 2^3 we get 10 and for 3^4 we get 15 and finally for 5^1 we get 3
by multiplying all 10*15*3=450
ans is 450. :)

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Jaya naga mahija  (5 years ago)

First do prime factorization for 3240.
2^3*5*3^4
multiply 2*5+5*3+3=10*15*3=450

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kaushik  (5 years ago)

450=5c2* 6c2*3C2

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priyadharshini  (5 years ago)

please, Anybody tell guys how it comes.....

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Priyanka Guggilam  (5 years ago)

5c2*6c2*3c2=450

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Billa prem  (5 years ago)

there are 3 no(condition not given for repetation)
_ _ _
inthe last no maybe 2,3,4 so 3 posible
inthe mid no maybe 2 3 4 so 3 posible
the first no may be 02 03 04,20,30,40,22,23,24,33,32,34,42,43,44 there 15 posible
so answer is 3*3*15=135

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