Latest Java Aptitude Question SOLUTION: Which checks the object code to determine whether there are more efficient means of execution? 1)Interpreter 2) Linker 3)Compiler 4) Optimizer

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Previous Question: Circles and Distances Problem Description Task is to calculate the straight line distance between the two objects moving in a circular path. They may move at different velocities. The distance has to be calculated after N seconds. The figure and commentary below it, explains the problem in detail. com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@491cde5b:image1.png We have two point objects B and C at rest on a straight line at a distance r1 and r2 units from a point A. At time t=0 seconds, the objects start moving in a circular path with A at the center with velocity v1 and v2 degrees per second. Given inputs v1, v2, r1 and r2, calculate the distance between the B and C after N seconds. Distance should be printed up to an accuracy of 2 places after the decimal point. Use Rounding Half-up semantics. Input Format First line contains velocity of object B in degrees per second (v1) Second line contains distance of object B from A (r1) Third line contains velocity of object C in degrees per second (v2) Fourth line contains distance of object C from A (r2) Fifth line contains time in seconds after which the distance between B and C, is to be measured (N) Output The distance between B and C, N seconds after they are set in motion Constraints v1, v2, r1, r2 > 0 and all are integer values. r2 > r1 0 < n <= 100 The objects move in anticlockwise direction v1, v2 <=360 r2 <= 100 Explanation Example 1 Input 90 5 270 10 1 Output 15.00 Explanation After 1 second, the object at B would cover 90 degrees and the object at C would cover 270 degrees. Both the objects would be vertically opposite to each other and would lie in a straight line. So the distance between them would be equal to the sum of their distance from the origin A=5+10= 15 Next Question: Find the nearest perfect square of the given number. Sample input:600 Sample output:576. Sample input:47011 Sample output:47089

(#M40166061) JAVA Programming question efficient means of execution Keep an EYE

Which checks the object code to determine whether there are more efficient means of execution?
1)Interpreter
2) Linker
3)Compiler
4) Optimizer: Asked In Java Mehul KOTHARI (1 year ago); Unsolved Read Solution (13); Is this Puzzle helpful? (33) (23) Submit Your Solution Technical

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Previous Question: Circles and Distances Problem Description Task is to calculate the straight line distance between the two objects moving in a circular path. They may move at different velocities. The distance has to be calculated after N seconds. The figure and commentary below it, explains the problem in detail. com.tcs.cv.automata.ei.middleware.DocxToHtmlConverter@491cde5b:image1.png We have two point objects B and C at rest on a straight line at a distance r1 and r2 units from a point A. At time t=0 seconds, the objects start moving in a circular path with A at the center with velocity v1 and v2 degrees per second. Given inputs v1, v2, r1 and r2, calculate the distance between the B and C after N seconds. Distance should be printed up to an accuracy of 2 places after the decimal point. Use Rounding Half-up semantics. Input Format First line contains velocity of object B in degrees per second (v1) Second line contains distance of object B from A (r1) Third line contains velocity of object C in degrees per second (v2) Fourth line contains distance of object C from A (r2) Fifth line contains time in seconds after which the distance between B and C, is to be measured (N) Output The distance between B and C, N seconds after they are set in motion Constraints v1, v2, r1, r2 > 0 and all are integer values. r2 > r1 0 < n <= 100 The objects move in anticlockwise direction v1, v2 <=360 r2 <= 100 Explanation Example 1 Input 90 5 270 10 1 Output 15.00 Explanation After 1 second, the object at B would cover 90 degrees and the object at C would cover 270 degrees. Both the objects would be vertically opposite to each other and would lie in a straight line. So the distance between them would be equal to the sum of their distance from the origin A=5+10= 15 Next Question: Find the nearest perfect square of the given number. Sample input:600 Sample output:576. Sample input:47011 Sample output:47089

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