Latest IBPS Aptitude Question SOLUTION: Tony, Monu and James completed a work together in 36 days and received a total payment of Rs. 54000. Tony took half of the total money, Monu took one third and James took remaining

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Previous Question: To make special tea, milk to water needed is in the ratio of 5 : 3. If a housewife had a mixture of milk and water in which the concentration of milk was 40% , then in what ratio this mixture should be mixed with pure milk to get the mixture suitable to make special tea? A) 2:3 B) 5:3 C) 1:2 D) 2:1 E) None of these Next Question: A solid cone is cut perpendicularly from the middle. If the height and volume of the whole solid cone before cut was 4√3 cm and 64√3 cm³ respectively, then find the total surface area of one of the cut portion. [Use π = 3] A) 19√3(4√3 + 1) cm² B) 16√3(3√3 + 1) cm² C) 18√3(5√3 – 2) cm² D) 16(3√3 + 1) cm² E) None of these

(#M40166418) IBPS Numerical Ability question Time and Work Keep an EYE

Tony, Monu and James completed a work together in 36 days and received a total payment of Rs. 54000. Tony took half of the total money, Monu took one third and James took remaining. In how many days, Tony and James would have finished the work if Monu was not working? A) 72 days B) 54 days C) 96 days D) 64 days E) Can not be determined: Asked In IBPS Devendra Marghade (4 years ago); Unsolved Read Solution (1); Is this Puzzle helpful? (4) (0) Submit Your Solution Time and Work

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Previous Question: To make special tea, milk to water needed is in the ratio of 5 : 3. If a housewife had a mixture of milk and water in which the concentration of milk was 40% , then in what ratio this mixture should be mixed with pure milk to get the mixture suitable to make special tea? A) 2:3 B) 5:3 C) 1:2 D) 2:1 E) None of these Next Question: A solid cone is cut perpendicularly from the middle. If the height and volume of the whole solid cone before cut was 4√3 cm and 64√3 cm³ respectively, then find the total surface area of one of the cut portion. [Use π = 3] A) 19√3(4√3 + 1) cm² B) 16√3(3√3 + 1) cm² C) 18√3(5√3 – 2) cm² D) 16(3√3 + 1) cm² E) None of these

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