Latest Elitmus Aptitude Question SOLUTION: WHY *NUT ------ OONP OYPY OUHA ---------- ONEPOP WHCH OF THESE NOT DIVISIBLE BY 2? a.W b.Y c.U d.N SIDES OF A TRIANGLE? a.NYT b.OWY c.EUO d.APW

W H Y
N U T
O O N P
O Y P Y
O U H A
O N E P O P
When you see second multiple (W H Y ) * U = (O Y P Y)

So, The number for U = 6 and Y is (2 , 4) Lets take the value of Y is 4 and replace it in figure.

W H 4
N 6 T
O O N P
O 4 P 4
O 6 H A
O N E P O P
Yes, this is some typical question we need more tries to reach solution.

Clearly if you see the yellow portion O + 6 = N and there is no carry to the next digit so we can confirm that ‘N’ is single digit number. If ‘N’ is single digit number ‘O’ should be less than (O < 3)

Let’s take O = 1 and redraw the table…

W H 4
N 6 T
1 1 N P
1 4 P 4
1 6 H A
1 N E P 1 P
If you observe the orange shaded region 1 + 6 = N & N + 4 = 1 so, we can clearly the value of N =7

So replace N = 7 and redraw the table.

W H 4
7 6 T
1 1 7 P
1 4 P 4
1 6 H A
1 7 E P 1 P
Take the third multiple (W H 4) * 7 = 1 6 H A à from this we get A = 8, and if you replace the H with 3 and w = 2 then the equation satisfies.

Like (2 3 4) * 7 = 1 6 3 8 so redraw the table with particular values.

2 3 4
7 6 T
1 1 7 P
1 4 P 4
1 6 3 8
1 7 E P 1 P
The remaining numbers are (0,5,9) It is simple to analyse we can’t get 5 in place of p because when you multiply with 4 we cannot get the last digit as 5.

So T = 5, P = 0, E = 9

After redraw the table.

2 3 4
7 6 5
1 1 7 0
1 4 0 4
1 6 3 8
1 7 9 0 1 0

N=7 is not divisible by 2

NYT 745 are sides of a triangle
because ,
7+4>5
7+5>4
5+4>7

w=2,h=3,y=4
n=7,u=6,t=5