Latest Elitmus Aptitude Question SOLUTION: A cow was standing on a bridge, 5 m away from middle of the bridge. A train was coming towards the bridge from the end nearest to the cow. seeing this the cow ran towards the train

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(#M40018192) ELITMUS Programming question ELITMUS MATHS PUZZLE Keep an EYE

A cow was standing on a bridge, 5 m away from middle of the bridge. A train was coming towards the bridge from the end nearest to the cow. seeing this the cow ran towards the train and managed to escape when the train was 2 m away from the bridge. If it had run in the opposite direction it would have been hit by the train 2m before the end of the bridge. What is the length of bridge in meters assuming speed of train is 4 times that of the cow.

Asked In Elitmus pavan (11 years ago)

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Glued Brain  (10 years ago)

Let the total length of the bridge be '2x'.
Now, the cow on seeing the train travels a distance of (x-5)m
Let the distance traveled by the train in the same time be 'y'
Since the time taken by the train and cow to travel a distance of (x-5)m and (y)m respectively is the same,
s1/y = s2/(x-5)---(1)
Given that s1 = 4s2---(2)
hence, solving 1 and 2 will yield 4x-y=20---(3)

Considering the second condition,
s1/((y+2)+(2x-2)) = s2/(x+5-2)
i.e. s1/(2x+y) = s2/(x+3)---(4)

solving 2 and 4 we get
2x-y= -12 ----(5)
Now, solving 5 and 3 we get x=16
Hence 2x = 32m is the answer..

Is this solution Helpfull? Yes (26) | No (1)  

abhishek pandey  (11 years ago)

length of the bridge will be 32 m.

Is this solution Helpfull? Yes (8) | No (3)  

vinod  (11 years ago)

let the length of the bridge is 2x
the initial position of cow is 5m left to the middle of the bridge
position of train is y mtrs left to the bridge,
when cow moves to the left..... distances traveled by cow, train before crossing are (x-5+2), (y-2) respectively.
let s1,s2 be the speeds of cow,train respectively. given s2=4s1.
as w.k.t distance, speed are directly proportional, (x-3)/(y-2)=s1/4s1
which gives 4x-y=10--------------------------(1)
If cow moves to the right,distances are (x+3),(y+2x-2) respectively.
similarly they gives 2x-y=-14-----------------(2)


from solving 1 & 2, x= 12, y= 38
so length = 2x = 24m

Is this solution Helpfull? Yes (4) | No (11)  

django  (11 years ago)

9.2m....equate distanc covered

Is this solution Helpfull? Yes | No (3)  

Rasmita Dash  (11 years ago)

A P O COW B TRAIN
|__|_______________|_______|_____________|....|X-3=(1/4)(6X-20)=>2x=8m

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naga sarath chand  (10 years ago)

i got 40m as length of the bridge.

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keerthana chennamsetty  (8 years ago)

i think 11m is the answer.

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sss  (7 years ago)

the answer would be 6 m and the equation would be
4x-20=y
2x-14=y
solving both u will get x=3 y=-8 , therefore, length of bridge id 2x=6m

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