Latest Elitmus Aptitude Question SOLUTION: compute the number of distinct ways in which 56 toffees can be distributed to Amit, Badri, Chetan, Duti, Erwin so that no person receives less than 10 toffees a 10c6 b 10c5

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(#M40018193) ELITMUS Numerical Ability question ELITMUS MATHS PUZZLE Keep an EYE

compute the number of distinct ways in which 56 toffees can be distributed to Amit, Badri, Chetan, Duti, Erwin so that no person receives less than 10 toffees

a 10c6
b 10c5

Asked In Elitmus pavan (11 years ago)

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Jasasri Kumari Pathy  (11 years ago)

No person should get less than 10 toffees.
so 50 toffees are distributed equally.
rest 6 toffes are to be distributed among 5 .
n=6(toffes) r=5(person)
(n+r-1)C(r-1)=(6+5-1)C(5-1)=(10)C(4)=(10)C(6)

Is this solution Helpfull? Yes (56) | No (1)  

Deepak kumar singh  (8 years ago)

nCr = selection of n distinct object r at a time.
But here 6 toffees identical. so we use (n+r-1 C r-1).
Here n=6,r=5
6+5-1 C 5-1 = 10 C 4 = 10 C 4
ans= a.10 c 6

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Rohit  (11 years ago)

No person should get less than 10 toffees.
so 50 toffees are distributed equally.
Rest 6 toffees are to be distributed .
To distribute 6 toffes (r), among 5 persons(n)
(n+r-1)C(r-1)=10C5 ways

Is this solution Helpfull? Yes (3) | No (32)  

Shashank  (6 years ago)

Each person should get atleast 10 toffees. So, 50 toffees are distributed equally among 5 people i.e 10 toffees to each person. 6 toffees are left now.
Number of ways of distributing n identical things among r persons when each person may get any
number of things = (n + r – 1) C (r–1)
Therefore, 6 identical toffees are distributed among 5 people i.e n=6 and r=5.
=> (n + r – 1) C (r–1)
=> (6+5-1) C (5-1)
= 10 C 6

Is this solution Helpfull? Yes (2) | No   

Anjali Sadhukhan  (8 years ago)

6c5.....as 6 toffees are to be distributed among 5 persons. please correct me if i am wrong :)

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