Latest Elitmus Aptitude Question SOLUTION: AGE * OAT ________ SOAR HOG- GOTO-- ________ GECOIR

317
*538
-------
**2536
**951*
1585**
----------
170546

thats an easy 1....

try to refer this material for cryptarithmetic problems.
http://cryptarithmetic.wordpress.com/

(i)Consider O+O+O=O, it's only possible iff O=0 or 5 but O=0 is not possible therefore O=5;Substitute the value in problem

(ii)Consider S+H+T=C, but since S+H+T cannot be greater than 27 therefore it cannot generate carry greater than 2 therefore E is either 6 or 7. But O*E=O i.e.
5*E(6 or 7)=5 therefore since E=6 is not possible E=7; Substitute in problem.

(iii)Consider O*A(i.e. 5*A = GE(including some carry from O*G(i.e.5*G)), therefore 1

ITS AN EASY ONE...
C=0,G=1,S=2,A=3,I=4,O=5,R=6,E=7,T=8,H=9

rohit wil u plz give me your no. I want to talk to u plzzz...

@ Pawan,

You can give ur number. I shall call you later.

9908680424

how to solve this kind of problems , plz some one suggest me which material study to solve !!

Hi Rohit, please tell me hoe to solve this type problem....
i wan tlk to u sir.
plze give me your contact number/ Email....plzzeee....sir.

pavan please give me ur no. or email id ......

ROHITH CAN U PLZZ TELL ME HOW TO SOLVE THESE TYPE OF PROBLEMS..... MY MAIL ID IS murali.kummitha@gmail.com

AGE
* OAT
________
SOAR

explain each alphabet how it s assigned by numbers pls.......

317
*538
-------
**2536
**951*
1585**
----------
170546

to solve this multiply indivisually T WITH= T*E=R,T*G=A,T*A=SO......(1)
multiply indivisually A WITH= A*E=G,A*G=O,A*A=H........(2)
multiply indivisually O WITH= O*E=O,O*G=T,O*A=GO.......(3)

Consider O+O+O=O, it's only possible if O=0 or 5 but O=0 is not possible BECOZ if we multiply 0 with AGE then all value of GOTO will be same ot means 0
AGE
* 0AT
________
SOAR
HOG-
0000--
________
GECOIR
here we had seen the changes while putting value if o is 0
therefore O=5;Substitute the value in problem

now its became:
AGE
* 5AT
________
S5AR
H5G-
G5T5--
________
GEC5IR

multiply indivisually T WITH= T*E=R,T*G=A,T*A=S5......(1)
multiply indivisually A WITH= A*E=G,A*G=5,A*A=H........(2)
multiply indivisually 5 WITH= 5*E=5,5*G=T,5*A=G5.......(3)


here we insert o=5

to solve this question easily we take equation 3 indivisually.
multiply indivisually 5 WITH= 5*E=5,5*G=T,5*A=G5.......(3)

5*E=_5
5*G+_=_T
5*A+_=G5

WHERE _ Is carry.

using hit & trial method
5*7=35
5*1+3=8
5*3+0=15

after getting result of 3rdd equation

you put this values in equation.


317
*5AT
________
SOAR
H5G-
1585--
________
G7C5IR

put valus of agec in all places

HERE IN 2ND step u had seen that when u put a=3 then u get the values of equation 2....


317
*53T
________
S53R
951-
1585--
________
17C5IR
NOW PUT THE VALUES IN EQUATION 1
U WILL GET OUTPUT.
317
*538
-------
**2536
**951*
1585**
----------
170546