Latest Accenture Aptitude Question SOLUTION: Q. At 10 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pmthe same dayy .if average speed of the faster train exceede

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Q. At 10 am 2 trains started travelling towards each other from station 287 miles apart they passed each other at 1:30 pmthe same dayy .if average speed of the faster train exceeded by 6 miles /hr what is speed of faster train in miles/hr

Asked In Accenture janvi sahu (11 years ago)

Solved soma Read Solution (5)

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Read Solution (5) :

soma   (10 years ago)

let the speed of slower train is x
then speed of faster train is=x+6
now, 287/x+x+6=7/2(3 and half hour)
after solving the equation we will get x=38
so faster train=x+6
38+6=44

Is this solution Helpfull? Yes (35) | No   

vinod  (11 years ago)

we will come to know that they each travel for 3.30 hrs= 7/2 hrs
sum of the distances traveled by both = 287 miles
s1, s2 are the speeds of the faster and slower train respectively

s1*(7/2)+s2*(7/2)=287...........(1)

given that s1=s2+6.................(2)

by solving (1)&(2)
s1= 44 miles/hr

Is this solution Helpfull? Yes (14) | No   

rama jha  (10 years ago)

let the speed of slower train be x
then the faster train will be x+6
difference in time is 3hr30 min=3.5hr
speed=distance/time
so,287=x*3.5+(x+6)*3.5=44 miles

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saurav dubey  (10 years ago)

the ans is 44 miles/hr
suppose the speed of slow train is x miles/hr,
then the speed of the fast train would be x+6 miles/hr.
now, they have traveled 287 miles
and the time taken would be 3 hours and 30 minute or 7/2 hour.
Thus applying the formula
Speed=(Distance / Time)
(x+(x+6))=(287/(7/2)).....eq (1)
by solving the above we get the ans as 44 miles/hour

Is this solution Helpfull? Yes (4) | No   

om anand  (9 years ago)

let the speed of slowest train be x miles/hr
speed of fastest train be x+6 miles/hr
now,
d/t=speed
287/3.5=82
then,x+x+6=82
x=38
fastest train speed will be x+6=44 miles/hr

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