Latest Elitmus Aptitude Question SOLUTION: We know that after nos n>4 the factorial for every n has trailing zeroes . We denote trailing zeroes by k. What value of k among 1 to 22 is not possible.

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(#M40018453) ELITMUS question Number System Keep an EYE

We know that after nos n>4 the factorial for every n has trailing zeroes . We denote trailing zeroes by k. What value of k among 1 to 22 is not possible.

Asked In Elitmus Sumit Rawal (11 years ago)

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Sumit Rawal  (10 years ago)

sry there are total 3 values which are possible 5,11,17 will explain it later

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Sumit Rawal  (10 years ago)

ohhh okk shweta 3 values not possilbe
firstly 5
for 4 values 20/5 =4(no of zeros
but for 5 values 25/5 + 25/25 =5+1 =6(5 values are never possible)
2ndly, 10 values 45/5+ 45/25 =9+1=10
but for 11 values 50/5 + 50/25=10+2=12(hence 11 values are never possible
For 16 values 70/5 + 70/25 =14+2 =16
But for 17 values 75/5 +75/25 =15+3 =18(hence 17 values are not possible )
so answer is 3 values (5,11,17)

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DIKSHA RANGNANI  (10 years ago)

5 and 16 is not possible

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shweta sharma  (10 years ago)

ms.diksha pls explain d answer

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Sumit Rawal  (10 years ago)

acc to my cal 5,11,16

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shweta sharma  (10 years ago)

@sumit thnx bt pls explain?

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farjana sayyed  (10 years ago)

can anyone tell me another way of solving this question?

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Pratyush  (10 years ago)

5,11,12,18

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