Latest Elitmus Aptitude Question SOLUTION: ABCD is a rectangle and APD is a I soscele triangle. angle APD is 100` ,diagonal AC has the twice length than CD. AC cuts PD at X .then what is the angle AXP?? A) 70 B)80 C)90 D)10

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(#M40018552) ELITMUS Numerical Ability question Keep an EYE

ABCD is a rectangle and APD is a I soscele triangle. angle APD is 100` ,diagonal AC has the twice length than CD. AC cuts PD at X .then what is the angle AXP??
A) 70 B)80 C)90 D)100

Asked In Elitmus Prakash Gupta (11 years ago)

Unsolved Read Solution (10)

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Read Solution (10) :

Sumit Rawal  (11 years ago)

The answer is 70 degrees. TO explain we need to draw a figure and after drawing figure it can be clearly inferred

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Mithun Kumar Kesari  (9 years ago)

70
in triangle APX
/_ PAX+/_ AXP=80
since any angle in a triangle must not be equal to zero
so /_ PAX != 0
and /_ AXP= 70

Is this solution Helpfull? Yes (4) | No (3)  

akanksha  (8 years ago)

i think this ques is practically impossible.If APD is 100 degrees and PAD is 90 degrees hoe can a triangle be formed???correct me if iam wrong

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suryakant kumar  (11 years ago)

70 DEGREE

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saikat rc  (11 years ago)

plz explain

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suryakant kumar  (11 years ago)

draw rectangle naming ABCD
APD IS A ISOS.. AND

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suryakant kumar  (11 years ago)

draw rectangle naming ABCD
APD IS A ISOS.. AND

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Cp Choudhary  (8 years ago)

Right @Akanksha..........I also think this question is not practically exist

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Rahul Tiwari  (8 years ago)

Your options are not correct

Correct ans will be 60 degree
It is not given in ur options but was there in elitmus question paper.

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Adil khan  (6 years ago)

Question is right you just have to draw the figure ans is 70 degree
I am trying to explain I hope u ll get it.
According the question triangle is Isocelles so one side is given 100 so another sud b 40 and 40.
Now one more clue give that AC is twice of CD it means trang ACD is right angle having angle 30 60 and 90
Now
Angle PAD=PAC+CAD
PAD is 40 and CAD IS 30 so PAC ll be 10
Now in PXD 180-100-10=70

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