Latest TCS Aptitude Question SOLUTION: 15 women or 10 men complete in 55 days .how many days 4 women & 5 men will take

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15 women or 10 men complete in 55 days .how many days 4 women & 5 men will take

Asked In TCS dipali (11 years ago)

Unsolved Read Solution (15)

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Devendra Marghade  (11 years ago)

71.739 days
1Woman,1Day work=1/(55*15),so 4Woman 1Day work=4/(55*15)
1Man , 1Day work=1/(55*10),so 5Men 1Day work=5/(55*10)
4 women & 5 men 1 Day work=[4/(55*15) + 5/(55*10)]=23/1650
So days to complete the work=1650/23=71 17/23 or 71.739

Is this solution Helpfull? Yes (29) | No (2)  

SHIVANI PRAKASH  (11 years ago)

1 woman,1 day work=1/55*15
1 man,1 day work=1/55*10
4 woman+5 men,1 day work=4/(55*15) + 5/(55*10)=23/1650
thus answer=1650/23 days

Is this solution Helpfull? Yes (12) | No   

k.m  (11 years ago)

in 412.5 days i think s.o

Is this solution Helpfull? Yes (5) | No (10)  

Chandni Maurya  (11 years ago)

ans= 71.739 days = 71 & 17/23 days
15 women work = 10 men work
1 woman work = 3/2 men work
15 women complete = in 55 days
1 woman will compllete = 55*15=825
(4 women + 5 men)=> 4 + 5*3/2 => 23/2 women will complete = 825/(23/2)
= 825*2/23
= 71.739
= 71 and 17/23 days

Is this solution Helpfull? Yes (3) | No (4)  

vinyosna  (11 years ago)

71.739 days..

bcoz w=1/(55*15) and m=1/(55*10)

4w+5m=1/71.739

Is this solution Helpfull? Yes (2) | No (1)  

shantanu shreshth  (11 years ago)

55/((4/15)+(5/10))=71.739127

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Devang  (11 years ago)

4/55+1/11=9/55

so,it v'll take 55/9 days

Is this solution Helpfull? Yes (1) | No (5)  

Pravin  (11 years ago)

72 days(approx)
1 men one day work=1/15*55=1/825
1 women one day work=1/10*55=1/550
5men and 4 women combine together time taken=1/[(5/550)+(4/825)] =71.74=72days(approx)

Is this solution Helpfull? Yes (1) | No (1)  

vijayraj  (11 years ago)

15 womens complete work in 55 days
10 men complete work in 55 days,
so one women can do 1/(55*15) of work each day,
and similarly one men can do 1/(55*10) of work each day,
and finally 4 women & 5 men can do
4*1/(55*15)+5* 1/(55*10) of work daily,
so total no of days will be reciprocal of answer,

Is this solution Helpfull? Yes (1) | No   

sujeet kumar keshri  (11 years ago)

1 women's 1 days work = 1/(55*15)
1 man's 1 days work = 1/(55*10)
thus 4 women & 5 men 1 day work = 4/(55*15) + 5/(55*10) =23/1650
no of days= 1650/23 =71.73

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Aditya Sadhukhan  (11 years ago)

ans=15*10*55/(4*10)+(15*5)=15*10*55/115=1650/23=71.729 days

Is this solution Helpfull? Yes (1) | No   

Sampa Ghosh  (11 years ago)

no of days =total days/((and/0r)+(and/or))
=55/(4/15+5/10)
=55/(23/30)
=55*30/23
=1650/23
=71.74
=78(approx)days

Is this solution Helpfull? Yes | No   

Lopa  (11 years ago)

4 woman-1 day- 4/(55*15)
5 man-1 day-5/(10*15)
therefore,4w&5m do (4/(55*15)+5/(10*15)) part of work in 1 day.So whole work will be done in 23.8 days or in 24 days.

Is this solution Helpfull? Yes | No (1)  

shaleen kumar  (11 years ago)

it can't be solved...as data is insufficient.

Is this solution Helpfull? Yes | No (3)  

rohit roshan  (11 years ago)

10 m=15 w so
5m=7.5 w
now total workers=4w+5m=4w+7.5w=11.5 w
total work=55*15=825w-days
so total days required= 825/11.5=71.7 approx 72 days

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