Latest TCS Aptitude Question SOLUTION: The number of votes not cast for the Praja Party increased by 25% in the National General Elections over those not cast for it in the previous assembly polls,and the Praja Party lo

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(#M40020000) TCS Numerical Ability question Vote puzzle Keep an EYE

The number of votes not cast for the Praja Party increased by 25% in the National General Elections over those not cast for it in the previous assembly polls,and the Praja Party lost by a majority twice as large as that by which it had won the assembly polls.If total of 2,60,000 people voted each time,how many voted for the Praja Party in the assembly elections?

Asked In TCS Chandan Kumar Nayak (10 years ago)

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bumbum  (10 years ago)

Let vote not cast for praja party in assembly poll = x
vote cast for praja party in assembly poll = (2,60,000-x)
vote not cast for praja party in Nation General Election = 1.25x
vote cast for praja party in Nation General Election =(2,60,000-1.25x)
praja party won the assembly poll by (2,60,000-x)-x votes
praja prty lost NGE by (1.25x-(2,60,000-1.25x))
so, 2(2,60,000-2x)=(1.25x-(2,60,000-1.25x))
5,20,000-4x=2.5x-2,60,000
x=1,20,000
In assembly election praja party got 2,60,000-1,20,000=1,40,000 votes

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Devendra Marghade  (10 years ago)

Ans=1,10,000
I)Votes in Previous Election:
Not Praja Party=x then Praja Party=260000-x ---(i)
II)Votes in Current Election:
Not Praja Party=1.25x ,Praja Party=260000-1.25x ---(ii)

Given Diff. in (i) when Praja Party won is twice as diff. in (ii) when lost
so 2(260000-x-x)=1.25x-(260000-1.25x) or
520000-4x=2.5x-260000 ,6.5x=780000 ,x=120000
So Votes for Praja Party in Current Election=260000-1.25x
=260000-1.25*120000=110000

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Chandan Singh  (10 years ago)

kehna kya chahte ho????????????????

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rajeev  (4 years ago)

can any one explain about question

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