Latest Wipro Aptitude Question SOLUTION: 16 men can complete a work in 24 days , while 48 children can do it in 16 days.12 men started the work , aftr 14 dats 12 children joined the.in how many days will all of them do th

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16 men can complete a work in 24 days , while 48 children can do it in 16 days.12 men started the work , aftr 14 dats 12 children joined the.in how many days will all of them do the remaining work ?

Asked In Wipro sujitha (10 years ago)

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Laxman Kompelli  (10 years ago)

16M=24D so 1M=384D
48CH=16D so 1CH=768D
so here we got 1M=2Ch
12M*14D=168D of work completed
remaining work 384D-168D=216D
12 childrens are added means 12CH=6M
so 12M+6M=18M
18M can complete 216D work in=216/18=12Days

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parminder maan  (10 years ago)

16 men can complete work in 24 days so 1 men 1 days work =1/16*24
similarly 1 children 1 days work=1/48*16
so 12 men work=1/16*24*12=1/32
14 day work of 12 men=1/32*14=7/16
total remaining work=9/16
12 children 1 day work=1/64
total 1 days work of 12 children and 12 men=1/32+1/64=3/64
so remaining work 9/16 can be done in 64/3*9/16=12 ans

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Nirmalaw  (10 years ago)

ans : 12
M1*D1=M2*D2=> 1 man=2 children then we have to find total work.
16M*24=16*2*24=768
12 men started work so 12m*14=12*2*14=336

768-336=432
then 12M+12C=12*2c+12C=36
remaing work/36
=432/36
=12

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anand kumar  (10 years ago)

16 men can do in one day=1/24
1 men can do in one day=1/(16*24)
similarly 1 child can do in one day=1/(16*48)
12 men can do work in 14 days=14*(12/16*24)=7/16
remaining work = 9/16
12 men and 12 child can do in one day = (1/32)+(1/64)=(3/2)*(1/32)
remaining work can be done = (9/16)*32*(2/3)= 12

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gayam.mahendra@gnail.com  (9 years ago)

hey is there any shortcut for this kind of time and work problems plz

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