Latest TCS Aptitude Question SOLUTION: 1!+2!+....50! =?

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(#M40023778) TCS question Keep an EYE

1!+2!+....50! =?

Asked In TCS amulya cutie (11 years ago)

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k.s.v.santosh kumar  (11 years ago)

sigma(n*n!)=(n+1)!-1 from n=1 to n
thus, for sigma(n!)..we can write it as (sigma(n*n!)/n), which is equal to ((n+1)!-1)/n.
now replace n=50
we get (51!-1)/50
this is the answer.

Is this solution Helpfull? Yes (6) | No (17)  

kalyani dangeti  (11 years ago)

summation of n factorial is given by the formula L!n(left factorial of n) which is defined as "permutation of n objects such that no object appears in its natural place" Ex:!3=2,since (1,2,3) be natural order,(2,3,1),(3,1,2) are only possible...L!n is also given by n!/e => !50=50!/e=1.118872e+64

Is this solution Helpfull? Yes (2) | No (2)  

yamuna.vankayalapati  (11 years ago)

in an A.P sum of first and last term is equal to the sum first 2nd term and 2nd last term viceversa till all the values are added
in this example:1!+50!=3.04140932*10^64
here num of values == 50
hence we have 50/2 values =25
multiply 25 with 3.04140932*10^64=7.6035233*10^65

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lakshmi srinivas  (11 years ago)

apply summation to n th term to get the value ...so we get 22100

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Deepa  (11 years ago)

apply to this formula... n(n+1)(2n+1)/6....

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HARSH  (11 years ago)

pls send me tcs apti papers 2013.......my id-rharsh170@gmail.com

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