Latest TCS Aptitude Question SOLUTION: A company's selection process is described below: Applicant-1: Accepted Applicant-2: Rejected Applicant-3: Accepted Applicant-4: Rejected Applicant-5: Rejected Applicant-6: Accepte

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A company's selection process is described below:
Applicant-1: Accepted
Applicant-2: Rejected
Applicant-3: Accepted
Applicant-4: Rejected
Applicant-5: Rejected
Applicant-6: Accepted
Applicant-7: Rejected
Applicant-8: Rejected
Applicant-9: Rejected
Applicant-10: Accepted

and so on

The company receives a total of N applicants and 5% of them are selected. Find the total no. of applications and total no. of selected candidates.

Asked In TCS Amrutha Duggirala (10 years ago)

Unsolved Read Solution (7)

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Shubhashish gaurav  (10 years ago)

1/2,2/(1+2),3/(1+2+3),4/(1+2+3+4)..........n/(1+2+3+....n),now
n/(1+2+3+4....n)*100=5 =2 n /n(n+1)*100 = 5.
so answer is put n=39 u wud get ur answer;

Is this solution Helpfull? Yes (16) | No (5)  

sarang singla  (10 years ago)

If 1 student got selected, then 1 rejected
If 2 students got selected, then 1+2 rejected
If 3 students got selected, then 1+2+3 rejected
If 4 students got selected, then 1+2+3+4 rejected
If n students got selected, then (1+2+3+4+...+n) rejected =n(n+1)/2 rejected

For n students to be selected, total students appeared is = students who got accepted + students who got rejected = n+n(n+1)/2

acceptance percentage, n/[n+n(n+1)/2]=5
solving it for n, we got n=37
Therefore accepted students are, n=37
total students are, n+n(n+1)/2 = 37+37(37+1)/2 = 740

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prabhashankarpandey  (10 years ago)

n=37 is correct
bcs accepted % till nth term ((n)/1+2+3....N+N)*100=5%

Is this solution Helpfull? Yes (6) | No (1)  

NAVYA  (10 years ago)

gaurav can u xplain the logic clearly

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juhe rawat  (10 years ago)

no of applicaition is N
no of selected candidate is 0.05N

Is this solution Helpfull? Yes | No (3)  

sravani  (10 years ago)

plz explain

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deevi.sriramya  (10 years ago)

mr.gaurav can u pls explain the logic clearly pls

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