Latest TCS Aptitude Question SOLUTION: Vinay dropped a ball from his terrace whose height is 50 meters if the height of the ball reduces to half after every contact with the ground. What is the total distance travelled

• Placement Papers
• /
• TCS
• /
• Numerical Ability
• /
• Time Distance and Speed

TCS Question Papers: TCS Interview Experience(91) TCS Company Profile

(#M40024924) TCS Numerical Ability question Keep an EYE

Vinay dropped a ball from his terrace whose height is 50 meters if the height of the ball reduces to half after every contact with the ground. What is the total distance travelled by the ball?

a. 75
b. 100
c. 150
d. 200

Asked In TCS ASD (11 years ago)

Solved amit Read Solution (13)

Is this Puzzle helpful?   (12)   (3) Submit Your Solution Time Distance and Speed

Read Solution (13) :

amit   (11 years ago)

s=50+2*50/2^1+2*50/2^2++2*50/2^3+....+2*50/2^infinite
s=50[1+1+1/2^1+1/2^2+1/2^3.......]
s=50+50[1+1/2^1+1/2^2+1/2^3.......]
s=a/1-r ->(infinte GP)
s=50+50[1/(1-1/2)]
s=150

Is this solution Helpfull? Yes (47) | No (5)  

sahithi  (11 years ago)

1) ball dropped from height of 50 mts height covered=50mts
2)it rebounce back to height of 25 mts and falls down from 25 mts so height covered here =25+25=50mts
3)it again rebounce to height of 12.5 mts and fall from 12.5 mts so height covered here =12.5+12.5=25
.
.
50,50,25,12.5....... excluding first 50 remaining series in gp(geometric progression)to infinity with common difference=0.5 so
sum=a/1-r
=50/1-0.5=100
by adding first 50 also we get total distance covered=50+100=150 meters

Is this solution Helpfull? Yes (35) | No   

Shubhi Agarwal  (11 years ago)

infinite gp of (50, 25, 12.5,....) + 50,
hence answe= 150

Is this solution Helpfull? Yes (16) | No (8)  

sandy  (11 years ago)

50+25+12.5+6.25+3.125+1.5625+0.78125+0.39+0.195+0.0976+0.0488+0.0244+0.0122+...
=100

Is this solution Helpfull? Yes (16) | No (24)  

ravindra mewada  (11 years ago)

series is 50+25+25+12.5+12.5+.........=50+2(25)+2(12.5).......
sum of infinite gp is a/1-r so 50+(2*(25)/.5)=150

Is this solution Helpfull? Yes (9) | No (1)  

Asit Shukla  (11 years ago)

Ans is 150

Is this solution Helpfull? Yes (6) | No (7)  

Aakash Srivastava  (11 years ago)

when goes downward: 50+25+12.5.....
When goes upward: 25+12.5....

so total distance = downward+upward

using GP sum : (50+25+12.5....)+(25+12.5....)
= 50*(1/1-.5) + 25*(1/1-.5)
=150

Is this solution Helpfull? Yes (6) | No   

supreetha bhushan  (11 years ago)

there is one short cut for problems like these...
formula is: area/(1-ratio)
solution: 2*(25/(1-0.5))+50 == 150
ratio is given 1/2
from 50/2=25 this occurs twice because of bouncing and 50m fall occur once so i have added it.

Is this solution Helpfull? Yes (3) | No (1)  

Vivek Prajapati  (11 years ago)

150

it forms two GPs as
((50/(1-1/2))+(25/(1-1/2)))

Is this solution Helpfull? Yes (1) | No   

apoorva deshpande  (11 years ago)

ans is 666.625rs
frst find CP of mixtre
20*30+40*25=1600
calcute 1/3 pice its 533.3rs
calulate nw SP
SP=125*533.3/100=666.625rs

Is this solution Helpfull? Yes | No (27)  

Guru Pranav  (11 years ago)

NO 150 will be the correct answer !!!

Is this solution Helpfull? Yes | No   

deepika singh  (9 years ago)

(50,25,12.5,6.25........) form g.p
ans is 150

Is this solution Helpfull? Yes | No   

Dhanraj  (9 years ago)

h(1+r/1-r) here h=50 r=1/2

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.