Latest Infosys Aptitude Question SOLUTION: ABC *DEF ----------- BFAE DGFEG ABCGG ---------- CHGFE ---------- A,B,C,D,E,F,G,H represent distinct integer from 0-9.and C+E=8.find 4A+3F+2B=? AB+CD+EF+GH=?

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ABC
*DEF
-----------
BFAE
DGFEG
ABCGG
----------
CHGFE
----------
A,B,C,D,E,F,G,H represent distinct integer from 0-9.and C+E=8.find
4A+3F+2B=?
AB+CD+EF+GH=?

Asked In Infosys liki mohanty (12 years ago)

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pankaj kumar  (12 years ago)

A=1
B=2
C=3
D=4
E=5
F=6
G=7
H=8
given as C+E=8
which follow the above given conditions
so 4A+3F+2B=4*1+3*6+2*2=26
similiarly
AB+CD+EF+GH=100
AB

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rk  (12 years ago)

THE MULTIPLICATION ACTUALLY IS:

ABC
*DEF
------
BFAE
DGFEG
ABCGG
------------
CHGFE

THAT MEANS G=0 FIRST OF ALL. AND D=1 BCOZ D*ABC=ABC
NOW,C+E=8 SO IT COULD BE 2,6 OR 6,2 OR 3,5 OR 5,3.(C CANT BE 0,1,7,8,9 AND 4 OTHERWISE E WILL ASLO BE 4)
F*C AND C*E BOTH RESULTS LAST DIGIT AS E. IN THIS CASE CANT BE 2 COZ THEN E WILL BE 6 AND 2*6 =12 LAST DIGIT 2.LETS CHECK FOR C=3 THEN E WILL BE 5.3*5=15
LAST DIGIT IS 5.ONE CONDITION IS FULFILLED.F*3 SHOULD RESULT IN LAST DIGIT AS 5.FOR THAT F WILL HAVE TO BE 5 ONLY WHICH IS NOT POSSIBLE AS E=5.
SAME CONDITION FOR C=5.FINALLY U GET C=6,THEN E=2.F*6 SHOULD RESULT IN LAST DIGIT 2.F HAS TO BE 7.
FROM THE MULTIPLICATION U CAN SEE THAT A+E=F THAT MEANS A=5.SO NOW IT BECOMES

5B6
*127
--------
B752
10720
5B600
----------
6H072

WITH VERY LITTLE TRIAL AND ERROR U CAN GET B=3 AND H=8.SO U HAVE
A=5,B=3,C=6,D=1,E=2.F=7,G=0 ANG H=8.
PUTTING THESE VALUES IN THE EQUN
4A+3F+2B=47

AB+CD+EF+GH=35

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