MnO4 oxidizes i oxalate ion in acidic medium at 333 K and and ii HCl For balanced chemical equations the

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MnO4
– oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical
equations, the ratios [MnO4
– : C2O4
2–] in (i) and [MnO4
– : HCl] in (ii), respectively, are-
(A) 1 : 5 and 2 : 5 (B) 2 : 5 and 1 : 8 (C) 2 : 5 and 1 : 5 (D) 5 : 2 and 1 : 8: Asked In KVPY (11 years ago); Unsolved; Is this Puzzle helpful? (1) (0) Submit Your Solution

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Latest KVPY Aptitude Question SOLUTION: MnO4 – oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical equations, the ratios [MnO4 – : C2O4 2–] in (i) and [MnO4 – : HCl] in (ii)

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(#M40027220) KVPY question Physical Ability Test Keep an EYE

MnO4
– oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical
equations, the ratios [MnO4
– : C2O4
2–] in (i) and [MnO4
– : HCl] in (ii), respectively, are-
(A) 1 : 5 and 2 : 5 (B) 2 : 5 and 1 : 8 (C) 2 : 5 and 1 : 5 (D) 5 : 2 and 1 : 8

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Latest KVPY Aptitude Question SOLUTION: MnO4 – oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical equations, the ratios [MnO4 – : C2O4 2–] in (i) and [MnO4 – : HCl] in (ii)

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(#M40027220) KVPY question Physical Ability Test Keep an EYE

MnO4 – oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical equations, the ratios [MnO4 – : C2O4 2–] in (i) and [MnO4 – : HCl] in (ii), respectively, are- (A) 1 : 5 and 2 : 5 (B) 2 : 5 and 1 : 8 (C) 2 : 5 and 1 : 5 (D) 5 : 2 and 1 : 8

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MnO4
– oxidizes (i) oxalate ion in acidic medium at 333 K and and (ii) HCl. For balanced chemical
equations, the ratios [MnO4
– : C2O4
2–] in (i) and [MnO4
– : HCl] in (ii), respectively, are-
(A) 1 : 5 and 2 : 5 (B) 2 : 5 and 1 : 8 (C) 2 : 5 and 1 : 5 (D) 5 : 2 and 1 : 8