Latest TCS Aptitude Question SOLUTION: what is remainder when 123412431234...(400 digits) is divided by 909?

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(#M40028932) TCS question Keep an EYE

what is remainder when 123412431234...(400 digits) is divided by 909?

Asked In TCS pre (10 years ago)

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sandeep kumar  (10 years ago)

1234%909=325;
12341234%909=650=325*2;
123412341234%909=325*3;
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12341234....................(repetation of 1234 100 times)=325*100=32500;
therefore,32500%909=685; that's it.
Always observe the pattern when there id periodic repetaion of digit are there.

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Rajan Kumar  (10 years ago)

if you divide 1234 by 909 u get remainder 325

so if u divide 100* 325 / 909 the remainder will be the same

32500/909 gives remainder 685

685 is the answer
if we divide 1234 by 909 the remainder will be 325.
now we have to do this 100 times.
so 32500/909 gives 685.
or...
32500/909 the integer part is 35
32500 - 35 * 909 = 32500 -31815 = 685

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RAKESH  (10 years ago)

1234/909=325*1
12341234/909=650=325*2
123412341234/909=(325*3)/909=66
1234123412341234/909=(325*4)/909=391
similarly
.......
..........
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123412341234...(400 digits) means 1234 100 times,so
123412431234...(400 digits)/909=325*100=32500
now dividing 32500 by 909 gives the reqd remainder which is 685

Is this solution Helpfull? Yes (7) | No (1)  

Biswajit Das  (10 years ago)

4 numbers "1234"placed after each...so in 400 digits the 4 digits from the last should be 1234...so 1234/909 is 325..so the answer should be 325..

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dipu  (10 years ago)

if 12341243/909 gives remainder=659
nd its occurs 50 times
so 659*50=32950
nd 32950/909=226
so ans is226

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Sagnik Raha  (10 years ago)

1234 occur 100 times so remainder will be 100*1234 mod 909=685

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RAJIV KR UTSAV  (10 years ago)

The ques is wrong if you carefully see the ques..The seventh digit should be 3 and the eight digit should be 4..

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Guru Pranav  (10 years ago)

The remainder is 685 !!!

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