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(#M40029077) TCS question round table logic Keep an EYE

If n person are seated at a round table then the probability that m particular person sit together is howmuch?

Asked In TCS swastik (11 years ago)

Unsolved Read Solution (11)

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Ananya  (11 years ago)

(n-m)!*m!/(n-1)!

Is this solution Helpfull? Yes (43) | No (3)  

Bhumi Chatterjee  (11 years ago)

take m as a 1 person,
so permutation=(n-m+1)!
m can be arranged as m!
total arrangement=m!*(n-m+1)!
sample space=(n-1)!
ans: ((n-m+1)!*m!)/(n-1)!

Is this solution Helpfull? Yes (21) | No (3)  

Manohar  (11 years ago)

I think (n-m)!*m!

Is this solution Helpfull? Yes (2) | No (3)  

ANURAG MONAL  (11 years ago)

@bhumi...its a round table so that u fixed a 1st sit ie 1 person,therefore
(n-m+1-1)!*m!/(n-1)! is the r8 ans......ANANYA u r r8!!!!

Is this solution Helpfull? Yes (2) | No   

shashank shekhar  (11 years ago)

circular permutation=n-1!
first we will fix m persons as 1.
now we are left with n-m persons.
don't forget to add m persons as 1 in n-m.
so we have (n-m+1-1)!/(n-1)!

Is this solution Helpfull? Yes (2) | No (1)  

swastik  (11 years ago)

Ananya you are right

Is this solution Helpfull? Yes (1) | No   

Aishwarya Gupta  (11 years ago)

i dont noe if i'm right but for circular arrangement if no of permutations is (n-1)! then for this particular case we we'll have (n-m-1)! in which m elements can also further be arranged in m! ways so the answere should ne (n-m-1)! m!

@ananya and bhumi why have you devided the answer with (n-1)!

Is this solution Helpfull? Yes (1) | No   

bipin mkumar  (11 years ago)

total number of space available for (n-m) artical= n-m+1;
we have choice to put one group(containing m member) at (n-m+1)space & m member can also be rearranged in themselfe so;
so tatal way=(n-m+1)P1*m!={(n-m+1)!/(n-m+1-1)!}*m! = {(n-m+1)!/(n-m)!}*m!

Is this solution Helpfull? Yes (1) | No (1)  

sagar biswas  (11 years ago)

(((n-m)+1)!*m!)/n!

Is this solution Helpfull? Yes | No (3)  

Saloni Singh  (11 years ago)

@aishwarya
because the qn is abt probability:favourable events /all possible events

Is this solution Helpfull? Yes | No   

Guru Pranav  (11 years ago)

(n-m)!*m!/(n-1)!

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