Latest C Aptitude Question SOLUTION: main() {i nt i=-1,j=-1,k=0,l=2,m; m=i++&&j++&&k++||l++; printf("%d %d %d %d %d",i,j,k,l,m); } Answer: 0 0 1 3 1 Explanation: Logical operations always give a result of 1 or 0. And

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(#M40029226) C question C Keep an EYE

main()
{i
nt i=-1,j=-1,k=0,l=2,m;
m=i++&&j++&&k++||l++;
printf("%d %d %d %d %d",i,j,k,l,m);
}
Answer: 0 0 1 3 1
Explanation: Logical operations always give a result of 1 or 0. And also the logical AND (&&)
operator has higher priority over the logical OR (||) operator. So the expression ‘i++ && j++ &&
k++’ is executed first. The result of this expression is 0 (-1 && -1 && 0 = 0). Now the
expression is 0 || 2 which evaluates to 1 (because OR operator always gives 1 except for ‘0 || 0’
combination- for which it gives 0). So the value of m is 1. The values of other variables are also
incremented by 1.

find output

Asked In C MAN (10 years ago)

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