Output main printf x 1

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Previous Question: output?? main() { char *p; printf("%d %d ",sizeof(*p),sizeof(p)); } Answer: 1 2 Explanation: The sizeof() operator gives the number of bytes taken by its operand. P is a character pointer, which needs one byte for storing its value (a character). Hence sizeof(*p) gives a value of 1. Since it needs two bytes to store the address of the character pointer sizeof(p) gives 2. Next Question: output? main() { char string[]="Hello World"; display(string); } void display(char *string) { printf("%s",string); } Answer: Compiler Error: Type mismatch in redeclaration of function display Explanation: In third line, when the function display is encountered, the compiler doesn't know anything about the function display. It assumes the arguments and return types to be integers, (which is the default type). When it sees the actual function display, the arguments and type contradicts with what it has assumed previously. Hence a compile time error occurs

(#M40029228) C question C Keep an EYE

output??
main()
{
printf("%x",-1: Asked In C MAN (10 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Latest C Aptitude Question SOLUTION: output?? main() { printf("%x",-1

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Programming and Technical

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(#M40029228) C question C Keep an EYE

output??
main()
{
printf("%x",-1

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