Latest C Aptitude Question SOLUTION: #include main() { char s[]={'a','b','c','\n','c','\0'}; char *p,*str,*str1; p=&s[3]; str=p; str1=s; printf("%d",++*p + ++*str1-32); } Answer: 77 Explanation: p is pointing to cha

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(#M40029232) C question C Keep an EYE

#include
main()
{
char s[]={'a','b','c','n','c',''};
char *p,*str,*str1;
p=&s[3];
str=p;
str1=s;
printf("%d",++*p + ++*str1-32);
}

Answer: 77

Explanation: p is pointing to character 'n'. str1 is pointing to character 'a' ++*p. "p is pointing to
'n' and that is incremented by one." the ASCII value of 'n' is 10, which is then incremented to
11. The value of ++*p is 11. ++*str1, str1 is pointing to 'a' that is incremented by 1 and it
becomes 'b'. ASCII value of 'b' is 98.
Now performing (11 + 98 – 32), we get 77("M"); So we get the output 77 :: "M" (Ascii is 77).

output??

Asked In C MAN (10 years ago)

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