Latest C Aptitude Question SOLUTION: output? #define clrscr() 100 main() { clrscr(); printf("%d\n",clrscr()); } A. 100 Explanation: Preprocessor executes as a seperate pass before the execution of the compiler. So t

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output?
#define clrscr() 100
main()
{
clrscr();
printf("%dn",clrscr());
}

A. 100

Explanation: Preprocessor executes as a seperate pass before the execution of the compiler.
So textual replacement of clrscr() to 100 occurs. The input program to compiler looks like this :
main()
{
100;
printf("%dn",100

Asked In C MAN (10 years ago)

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