Output n define f g g2 g g2 nmain n i nnt var12 100 nprintf d f var 12 n

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Previous Question: Q. #include main() {i nt i=1,j=2; switch(i) { case 1: printf("GOOD"); break; case j: printf("BAD"); break; } } A. Compiler Error: Constant expression required in function main. Explanation: The case statement can have only constant expressions (this implies that we cannot use variable names directly so an error). Note: Enumerated types can be used in case statements Next Question: Q. main() {i nt i=0; for(;i++;printf("%d",i)) ; printf("%d",i); } A. 1 Explanation: before entering into the for loop the checking condition is "evaluated". Here it evaluates to 0 (false) and comes out of the loop, and i is incremented (note the semicolon after the for loop).

(#M40029266) C question C Keep an EYE

output?
#define f(g,g2) g##g2
main()
{i
nt var12=100;
printf("%d",f(var,12));
}
Answer: 100: Asked In C MAN (11 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Time: 00:01:33

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Latest C Aptitude Question SOLUTION: output? #define f(g,g2) g##g2 main() {i nt var12=100; printf("%d",f(var,12)); } Answer: 100

C Question Papers:

Programming and Technical

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Category (16)

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Numerical Ability (12)

Programming (218)

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(#M40029266) C question C Keep an EYE

output?
#define f(g,g2) g##g2
main()
{i
nt var12=100;
printf("%d",f(var,12));
}
Answer: 100

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