Q Predict the output or error nmain n nint i 5 j 6 z nprintf d i j n n

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Previous Question: Q. Predict the output or error A. main() { main(); } A. Runtime error : Stack overflow. Explanation: main function calls itself again and again. Each time the function is called it's return address is stored in the call stack. Since there is no condition to terminate the function call, the call stack overflows at runtime. So it terminates the program and results in an erro Next Question: Q. Predict the output or error main() { int k=1; printf("%d==1 is ""%s",k,k==1?"TRUE":"FALSE"); } A. 1==1 is TRUE Explanation: When two strings are placed together (or separated by white-space) they are concatenated (this is called as "stringization" operation). So the string is as if it is given as "%d==1 is %s". The conditional operator( ?: ) evaluates to "TRUE".

(#M40029345) C question C Keep an EYE

Q. Predict the output or error
main()
{
int i=5,j=6,z;
printf("%d",i+++j);
}

A. 11

Explanation:the expression i+++j is treated as (i++ + j): Asked In C MAN (11 years ago); Unsolved; Is this Puzzle helpful? (0) (0) Submit Your Solution

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Latest C Aptitude Question SOLUTION: Q. Predict the output or error main() { int i=5,j=6,z; printf("%d",i+++j); } A. 11 Explanation:the expression i+++j is treated as (i++ + j)

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(#M40029345) C question C Keep an EYE

Q. Predict the output or error
main()
{
int i=5,j=6,z;
printf("%d",i+++j);
}

A. 11

Explanation:the expression i+++j is treated as (i++ + j)

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