Latest TCS Aptitude Question SOLUTION: G and m can paint 720 box in 20 days ,m and h in 24 days and h and g in 15 days .g works for 4 days, m for 8 days, h for 8 days .find total no of boxes painted by them?

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G and m can paint 720 box in 20 days ,m and h in 24 days and h and g in 15 days .g works for 4 days, m for 8 days, h for 8 days .find total no of boxes painted by them?

Asked In TCS TCS 2014 (10 years ago)

Solved Shuvadip Lahiri Read Solution (5)

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Shuvadip Lahiri  (10 years ago)

g + m= 36 (720 in 20 days means 36 in 1 day)
similarly,
m + h= 30 and h + g= 48
solve these 3 equations to get m=9, g=27, h=21
now g works for 4 days , so no of boxes painted by g will be 27*4= 81
m for 8 days so 9*8= 72
h for 8 days so 21*8= 168
add them all...ans is 348.

Is this solution Helpfull? Yes (58) | No (1)  

RAKESH  (10 years ago)

no of boxes painted in 1 day by
g+m=720/20=36
m+h=720/24=30
h+g=720/15=48
adding these three 2(g+h+m)=114
or g+h+m=57
so g=27
h=21
m=9
so 4*g+8*m+8*h=4*27+8*9+8*21=108+72+168=348
total no. of boxes painted by them=348

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Soma Ghosh  (10 years ago)

ans:348
g,m and h together paint 57 boxes in 1hr
so g paints 27 boxes in 1hr
h 21
nd m 9 boxes
so total boxes required 27*4+21*8+9*8=348 boxes

Is this solution Helpfull? Yes (3) | No (1)  

RAKESH  (10 years ago)

no of boxes painted in 1 day by
g+m=720/20=36
m+h=720/24=30
h+g=720/15=48
adding these three 2(g+h+m)=114
or g+h+m=57
so g=27
h=21
m=11
so 4*g+8*m+8*h=4*27+8*11+8*21=108+88+168=364
total no. of boxes painted by them=364

Is this solution Helpfull? Yes (1) | No (10)  

Guru Pranav  (10 years ago)

Total number of boxes were 368

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