Latest Elitmus Aptitude Question SOLUTION: y=(log (log a base p ) base a)/(log (log p base a) base p). find y?

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(#M40030040) ELITMUS question elitmus quant 11/10/2013 Keep an EYE

y=(log (log a base p ) base a)/(log (log p base a) base p). find y?

Asked In Elitmus Amardip Gautam (11 years ago)

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VIKASH KUMAR SINGH  (11 years ago)

y=((log(log a base p))/log a)/((log(log p base a))/log p)
y=(log p(log log a - log log p))/(log a(log log p - log log a))
y= -(log p/log a)
y= - (log p base a)

Is this solution Helpfull? Yes (13) | No (2)  

naga sarath chand  (11 years ago)

ans is -1. since denominator = -(numerator).

Is this solution Helpfull? Yes (4) | No (2)  

rittwik ghosh  (11 years ago)

y=log p base a

Is this solution Helpfull? Yes (4) | No (4)  

Akshay Kumar Singh  (11 years ago)

(log a base p)/(log a) =x;
(log p base a)/(log p) =y;
x/y=z;
z=log a base p; ans

Is this solution Helpfull? Yes (2) | No (1)  

Amardip Gautam  (11 years ago)

each of the options contain log of something to the base something... so sry NAGA SARATH CHAND... yours wrong ans

Is this solution Helpfull? Yes (1) | No (1)  

Rounak Bhattacharjee  (11 years ago)

ne 1 plz solve this...

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Amardip Gautam  (11 years ago)

Applying formula.... log x base y = log x base e/log y base e,

y=[log(log a base p)base e/log a base e] / [log(log p base a)base e/log p base e]
since,log (log a base p) base e = log a base p
=>y=(log a base p/log p base a)*(log p base e/log a base e)
=>y=[(log a base e/log p base e)/(log p base e/log a base e)]*(log p base e/log a base e)
=>y=log p base e/log a base e
=>y=log p base a

Is this solution Helpfull? Yes | No (1)  

Prakhar Gautam  (11 years ago)

ans is log p base a. u can check ur ans by substituting p=2 and a=4.

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YARLAGADDA VAMSI KRISHNA  (11 years ago)

y= log(log a base p base a)/log(log p base a base p)

y= log(log a/log p * log a/log p)/log(log p/log a * log p/log a)

y=log(log a/log p)/log(log p/log a)== -log(log p/log a)/log(log p/log a)=-1.

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