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(#M40030040) ELITMUS question elitmus quant 11/10/2013 Keep an EYE

y=(log (log a base p ) base a)/(log (log p base a) base p). find y?

Asked In Elitmus Amardip Gautam (11 years ago)

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VIKASH KUMAR SINGH  (11 years ago)

y=((log(log a base p))/log a)/((log(log p base a))/log p)
y=(log p(log log a - log log p))/(log a(log log p - log log a))
y= -(log p/log a)
y= - (log p base a)

Is this solution Helpfull? Yes (13) | No (2)  

naga sarath chand  (11 years ago)

ans is -1. since denominator = -(numerator).

Is this solution Helpfull? Yes (4) | No (2)  

rittwik ghosh  (11 years ago)

y=log p base a

Is this solution Helpfull? Yes (4) | No (4)  

Akshay Kumar Singh  (11 years ago)

(log a base p)/(log a) =x;
(log p base a)/(log p) =y;
x/y=z;
z=log a base p; ans

Is this solution Helpfull? Yes (2) | No (1)  

Amardip Gautam  (11 years ago)

each of the options contain log of something to the base something... so sry NAGA SARATH CHAND... yours wrong ans

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Rounak Bhattacharjee  (11 years ago)

ne 1 plz solve this...

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Amardip Gautam  (11 years ago)

Applying formula.... log x base y = log x base e/log y base e,

y=[log(log a base p)base e/log a base e] / [log(log p base a)base e/log p base e]
since,log (log a base p) base e = log a base p
=>y=(log a base p/log p base a)*(log p base e/log a base e)
=>y=[(log a base e/log p base e)/(log p base e/log a base e)]*(log p base e/log a base e)
=>y=log p base e/log a base e
=>y=log p base a

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Prakhar Gautam  (11 years ago)

ans is log p base a. u can check ur ans by substituting p=2 and a=4.

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YARLAGADDA VAMSI KRISHNA  (11 years ago)

y= log(log a base p base a)/log(log p base a base p)

y= log(log a/log p * log a/log p)/log(log p/log a * log p/log a)

y=log(log a/log p)/log(log p/log a)== -log(log p/log a)/log(log p/log a)=-1.

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