Latest Elitmus Aptitude Question SOLUTION: A greatest 4 digit number when divided by 10, 15, 22 leaves remainder 4, 9, 10. What is the middle two numbers of that number. eg from abcd, what is bc?

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(#M40030080) ELITMUS Numerical Ability question Keep an EYE

A greatest 4 digit number when divided by 10, 15, 22 leaves remainder 4, 9, 10. What is the middle two numbers of that number. eg from abcd, what is bc?

Asked In Elitmus Sagar Dasari (10 years ago)

Unsolved Read Solution (9)

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Read Solution (9) :

Abinash kumar  (10 years ago)

you can solve it through options, and if you divide 9954 by the 10,15,22 they will give remainder as 4,9,10..respectively
my suggestion will be d'ont break ur head in thinking too much just go through options and get the answer.
cheers
all d best

Is this solution Helpfull? Yes (24) | No (2)  

mohana  (10 years ago)

ans:89
i think the reminders r 4,9,16 then the
10-4=6
15-9=6
22-16=6
greatest 4digit no. is 9999
lcm of 10,14,22 is 330
9999/330 gives the reminder 99
9999-99=9900 which is exactly divided by 10,15,22
when 9900-6=9894.
therefore the middle two numbers are 89

Is this solution Helpfull? Yes (14) | No (21)  

Mohit  (10 years ago)

its 95

Is this solution Helpfull? Yes (12) | No   

ramyasree  (10 years ago)

greatest number is 9954,middle two numbers are 95

Is this solution Helpfull? Yes (7) | No   

Shubham Raj  (8 years ago)

ans - 95
let take ' N ' is four digit no
(let a,b,c are quotient)
so , forming equation , N =10a + 4 --> 4,14,24,34,44,54,64 (lets take a=0,1,2,3,4,5,6,-,-,----
N =15b + 9 ------> 9,24,39,54,69
and N =22c + 10 -------> 10,32.54,76
common term is = 54 (from eqn of all three N)
general form of N = Lcm (of all dividend no ) * Y + common no
N = Lcm(10,15,22) * y + 54
=> N = 330y + 54
now again use hit and trial method for y (for forming four digit no)
take y=30
therefore N = 330*30 +54 =9954 (abcd)
bc=95

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Anjali Sadhukhan  (8 years ago)

10-4 , 15-9,22-10 ..and l.c.m of that..so lcm is 12..now devide 9999 by 12.which results 3 as remainder..subtracting that the number comes 9996.so middle two are 99 itself.

Is this solution Helpfull? Yes (3) | No (1)  

Lakhi kant Roy  (8 years ago)

Let N=4-digit no.
N=10*a+4
N=15*b+9
N=22*c+10
in these 3 equation we have a comman tern,i.e,54
In this case,General form will be-->N=Lcm(10,15,22)*y+54
=330*y+54
=330*30+54
=9954(abcd)
so,middle term,i.e,bc=95

Is this solution Helpfull? Yes (2) | No   

Ayush Sood  (10 years ago)

Answer is 80. since he doubled every body else's coind so intially other 3 players would have 16 coins each. So he have to give 16,16,16 coins to everybody i.e 48 and he is also left with 32 coins. So initially he must have 48+32=80 coins

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swati singh  (6 years ago)

See rs agarwal boom easiest method at starting of pages

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