Latest Elitmus Aptitude Question SOLUTION: 9. 4 gamblers A, B, C, D are playing with a condition of whoever looses the game doubles all other players money. At the end everybody has 32 coins. then what was initial coins w

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(#M40030093) ELITMUS Numerical Ability question Keep an EYE

9. 4 gamblers A, B, C, D are playing with a condition of whoever looses the game doubles all other players money. At the end everybody has 32 coins. then what was

initial coins with A.

Asked In Elitmus Sagar Dasari (10 years ago)

Unsolved Read Solution (8)

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Smruti Ranjan Pardhi  (10 years ago)

a,b,c,d - initial money with abcd
after a loses - a,2b,2c,2d
after b loses - 2a,2b,4c,4d
after c loses - 4a,4b,4c,8d
after d loses - 8a,8b,8c,8d
So, 8a=32, so a=4

Is this solution Helpfull? Yes (29) | No (6)  

tri  (10 years ago)

if A is 1st one to loose then ABCD have 66 , 34, 18, 10 respectively. has o be done by backtracking 32 32 32 32 --> 80 16 16 16 --> 40 72 8 8 --> 20 36 68 4 --> 10 18 34 66 --> D C B A

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Abhishek Kumar Gupta  (10 years ago)

1st at last they have 32 coin
then IN last game D would lose then it would have 16 *3 coin + 32=80
in 2nd last C would lose
similarly
making Table
last 32 32 32 32
D 16 16 16 80
C 8 8 72 40
B 4 68 36 20
A 66 34 18 10

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Sagar Dasari  (10 years ago)

sorry for incomplete question, they loose according to alphebitical order, that 1st A, 2nd B, then C & last D

Is this solution Helpfull? Yes (4) | No (2)  

shubhi garg  (10 years ago)

4 coins, not very sure though

as if u take conditions assuming that all have the same no. of coins initially as no case satisfies the given condition if different no. of coins are taken for all, so i assume all take equal no. of coins initially.

Then if initially A,B,C,D have 4 coins each, then when A loses he doubles other, then if B loses he doubles, thn c loses, and then d.

else there can be a condition where A has 32 coins and loses all the game.
so depends on option available.

my ans is 4 or 32

Is this solution Helpfull? Yes (1) | No (5)  

tri  (10 years ago)

SMRUTI RANJAN PARDHI when somebody loses we need to distribute his money to other (given in the question)... At the end total money should remain same

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Trisha  (10 years ago)

initially let ,
A has x coins, B has y coins, C has z coins, D has w coins,
After D losses, they have 2x, 2y, 2z coins resp. Again when c losses(or any) , they have 4x and 4y coins. again loss, the last one has 8x coins. So, 8x=32 or x =4, or y=8, or z=16 or w=32

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Zeeshan Ahmad Ansari  (4 years ago)

its so simple first take r=1 if r=1 then c =7,3 or l=is 3,7 you can put both the case and take if you check you will get the value of c=7 if c=7 then z=8 you can easily take it and if you put the value of z=8 then you will get the value of b=4 and now you can find the solution easily just put it and check it

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