Latest NIIT Aptitude Question SOLUTION: Q. The sum of a two digit number and the number formed by reversing its digits is 110.if the tens digit is 2 more than the units digit. find the number? Option a) 64 b) 46 c) 2

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Q. The sum of a two digit number and the number formed by reversing its digits is 110.if the tens digit is 2 more than the units digit. find the number?

Option
a) 64
b) 46
c) 24
d) 42

Asked In NIIT Nitin Kumar (11 years ago)

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Anitesh Kumar  (9 years ago)

(10x+y)+(10y+x)=110
so that 11x+11y=110
x+y=10.........(1)
x=y+2........................(2)

So that x=6,y=4;
Number =64

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Mahesh  (11 years ago)

Difference of a number and its reverse is always a multiple of 9 and difference of digits.
Same logic applies when we add a number and its reverse, it will always be 11 times the sum of digits.
As, the result is 110, the sum of digits is 110/ 11 = 10
Now the sum of digits is 10 and difference of digits is 2, so the digits are 6 and 4.
The number is 64.

Is this solution Helpfull? Yes (3) | No   

naveen kumar  (9 years ago)

10x+y+10y+x=110............(i)
y=2+x......................(ii)
solving i & ii
ans 24

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Avanish Kumar Dwivedi  (8 years ago)

Two digit number let say (10x+y).
Now ATP : 10x+y +10y+x = 110;
11(x+y) = 110.
Hence, x+y = 10;
second condition i.e tens digit is 2 more than unit digit. So answer is 46.

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