Latest TCS Aptitude Question SOLUTION: f(f(n))+f(n)=2n+3 and f(0)=1. then what is the value of f(2012)?

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f(f(n))+f(n)=2n+3 and f(0)=1. then what is the value of f(2012)?

Asked In TCS PRIYA NAMDEO (10 years ago)

Solved MANISH KUMAR Read Solution (7)

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Read Solution (7) :

MANISH KUMAR  (10 years ago)

ans:2013
put n=0
f(f(0))+f(0)=2(0)+3 ............given f(0)=1
f(1)+1=3
f(1)=2

now put n=1
f(f(1))+f(1)=2(1)+3 ......... since we found f(1)=2
f(2)+2=5
f(2)=3

similarly.....f(2012)=2013..... answer

Is this solution Helpfull? Yes (46) | No   

NarpatSingh  (10 years ago)

f(0)=1,so f(f(0))+f(0)=3 by putting n=0 so f(1)=2
now put n=1 then we get f(2)=3 so we can say f(2012)=2013

Is this solution Helpfull? Yes (3) | No   

Mahesh  (10 years ago)

f(0) = 1;
f(f(0)) + f(0) = 2(0) +3
f(1) + 1 = 3 ( By replacing f(0)=1)
so, f(1) =2

By applying the same logic,
f(f(1)) + f(1) = 2(1) + 3
f(2) + 2 = 5 ( By replacing f(1) = 2)
So, f(2) = 3

By applying similar logic, f(3) = 4 , f(4)= 5 and so on
f(2012) = 2013
Answer is 2013

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ganesh chemanchula  (10 years ago)

f(0)=1
f(1)=2
f(2)=3
like wise f(2012)=2013

Is this solution Helpfull? Yes (1) | No   

haritha Boyapati  (10 years ago)

ans is 2013

Is this solution Helpfull? Yes | No (1)  

mahendra kumar  (10 years ago)

Put n = 0
Then f(f(0))+f(0) = 2(0) + 3 ⇒ f(1) + 1 = 3 ⇒ f(1) = 2
Put n = 1
f(f(1)) + f(1) = 2(1) + 3 ⇒ f(2) + 2 = 5 ⇒f(2) = 3
Put n = 2
f(f(2)) + f(2) = 2(2) + 3 ⇒ f(3) + 3 = 7 ⇒ f(3) = 4
......
f(2012) = 2013

Is this solution Helpfull? Yes | No (1)  

krishna  (10 years ago)

2013

i know it will be 2013

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