Latest TCS Aptitude Question SOLUTION: if a series is given 1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,..... then which no will be at 2320th position?

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if a series is given 1,2,2,3,3,3,4,4,4,4,1,1,2,2,2,2,3,3,3,3,3,3,..... then which no will be at 2320th position?

Asked In TCS PRIYA NAMDEO (11 years ago)

Solved RAKESH Read Solution (9)

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Read Solution (9) :

Amit Kumar  (11 years ago)

Let consider 1st sequence 1-1,2-2,3-3,4-4 = total 10 terms
Similarly 2nd and 3rd sequence contain 20 terms and 30 terms.
So the series in A.P
10,20,30,40,....
10(1+2+3+4+......+n)=x where x is the near value to the given 2320th term
So 10{n(n+1)/2}=x (near to 2320)
By trail and error method we get n = 21
and x = 2310
no terms = 2320-2310 = 10
as 21 is completed 22 is started.
So 1-22,
So the number is 1

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RAKESH  (11 years ago)

no. of 1,2,3,4
1+2+3+4=1*10=10
2+4+6+8=2*10=20
3+6+9+12=3*10=30

now 10+20+30+......+10n=2320
or 10[n(n+1)/2]=2320
or n(n+1)=464
if n=20,20*21=420
n=21,21*22=462
10+20+30+....+210=10*21*11=2310
so from 2301 onwards 22 terms will be 1
hence 2320th term=1
ANS 1

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vinayakgupta  (11 years ago)

as we see the series element is doubling itself after 4 i.e 1,2,2,3,3,3,4,4,4,4 then 1,1,2,2,2,2,3,3,3,3,3,3,4,4,4,4,4,4,4,4 i.e the total no. of terms increasing are as 10,20,40,80,160,320,640,1280.........so till 640 we have sum as of 1270 terms remaing are 1050 that will b sub. frm 2320-1270 so we have to cal. 1050th term frm 1280 i.e 128(1's)+256(2's)+384(3's)+512(4's) so 128+256+384 will yield 758 i.e not 1050th term that means it falls in 512(4's) therefor ans is "4"

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pankaj bajaj  (11 years ago)

ans-3 bcz 1 2 2 3 3 3 4 4 4 4=10...it just double in nxt step
so we have series like this....
10 where 1 is 1 time
20 where 1 is 2 time
40
80
160
320
640...

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kratika jain  (11 years ago)

ans=4
1 2 2 3 3 3 4 4 4 4 =10 no.
11222333344444=15 no.
.
.
.
..........=5*464=2320 (implies series is just completed)
therefor 2320th no. is 4

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Nitika Sharma  (11 years ago)

the answer will be 1
As you can see from the series that number of terms will be like
10, 20, 30, 40 and so on
so 2300 will be the number of terms in the 230th line
where there will be 230 1`s
so the 2320 term will be 1.

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Surbhi khandelwal  (11 years ago)

solution ?

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MANOH SAHU  (11 years ago)

ANS:- 1 BY MANOJ SAHU

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deepak  (10 years ago)

10 nos in which 1 ones 2 twos ... 4 fours
30 nos double alls
60
120
240
480
960 till here total 1900
the next is 1920 in same sequence with 128 1's 256 2's and 512 3's and 1024 4's
but we need 2320 so more 400
128+256 makes 384 So it is obvious 2320 that it lies in 512 3's.
So the answer is 3

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