Latest TCS Aptitude Question SOLUTION: 2 workers, one young and one old, live together and work at the same office. It takes 20 minutes for the young man to walk to office. The old man takes 30 minutes for the same dist

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2 workers, one young and one old, live together and work at the same office. It takes 20 minutes for the young man to walk to office. The old man takes 30 minutes for the same distance. When will the young man catch up with the old man, if the old man starts at 10:00 a.m. and the young man start 10:05 a.m.?

Asked In TCS Alok sahoo (10 years ago)

Solved satish Read Solution (12)

Is this Puzzle helpful?   (12)   (2) Submit Your Solution Time Distance and Speed

Read Solution (12) :

satish  (10 years ago)

Distance = Speed * Time;
Let the distance will be 30m between Home and Office,
Hence Old Man's speed is 1m/min
and Young Man's speed is 1.5m/min

Old man starts at 10:00, and Young man starts at 10:05,

Old man travels 5m, Young man travels 0m at 10:05;
Old man travels 10m, Young man travels 7.5m at 10:10;
Old man travels 15m, Young man travels 15m at 10:15;

So both will meet at 15m apart from home at 10:15 A.M

Is this solution Helpfull? Yes (36) | No   

krittika  (10 years ago)

we know (speed ratio)=1/(time ratio)
sy/so=30/20=3/2

sy=3m/min
so=2m/min
let they meet after x time of start of old man
as they travel equal dist

2*x=3*(x-5)

x=15
at 10:15

Is this solution Helpfull? Yes (13) | No   

bhanu   (10 years ago)

x/30*t=x/20*(t-5)

Is this solution Helpfull? Yes (5) | No (1)  

MOHAMMED SHAHENSHA  (10 years ago)

distance is samei.e;"d"
d=s*t
s1t1=s2t2
dt/30=d(t-5)/20
t=15
at min. of t=10 ie;10:15 am

Is this solution Helpfull? Yes (3) | No   

VIPUL KUMAR  (10 years ago)

10:15 a.m.

Is this solution Helpfull? Yes (2) | No   

Midhun golla  (10 years ago)

common between two numbers i.e LCM of 20 and 30 is 10,in fact they will meet at 10 min,if both start at 10:00 but young man started late for 5 min so,10+05=15 min

Is this solution Helpfull? Yes (2) | No   

arunkumar  (10 years ago)

simple ratio equation
ratio in speed between young and old:20:30=2:3
so old and young will meet at 10:15am

Is this solution Helpfull? Yes (1) | No   

Alok sahoo  (10 years ago)

please explain

Is this solution Helpfull? Yes | No (1)  

vimal  (10 years ago)

please elaborate ur answer

Is this solution Helpfull? Yes | No   

mani  (10 years ago)

10:25 am young will catch the old

Is this solution Helpfull? Yes | No (2)  

sravani  (10 years ago)

let young 1.5 m/min old 1m/min
Time Distance
young old
10 0 0
10:05 5 0
10:10 10 7.5
10:15 15 15

Is this solution Helpfull? Yes | No   

TANVI  (9 years ago)

@arun kumar.....plz elaborate ur ans

Is this solution Helpfull? Yes | No (1)  

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