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TANVI to Inline Geek 11 years ago

A can complete a project in 20 days while B can complete same project in 30 days. If A and B start working together and A leaves the work 10 days before completion of project, then in how many days the project will be completed?

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Inline Geek 11 years ago

in one day A completes 1/20th of work, and B completes 1/30th of work. if both works together then work completed in one day will be =
1/20 + 1/30 = 1/12

that means it will take 12 days to complete the work when working together.
but A leave 10 days before actual completion of work that means after A leaves, B has to work 10 more days to complete the work means i.e. 1/3rd of the work.
that means 2/3rd of work is done by both together so number of days:

= no. of days (A & B) + no of days( B alone)
= 12 * (2/3) + 10 = 18 days

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TANVI to karthikeyank 11 years ago

Reply Like? Yes (1) | No

TANVI to RAKESH 11 years ago

a b c d e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299. then a+B+C+D+E =?

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mohan bylapudi 11 years ago

2299=11*11*99
so u have to write (75-a)(75-b)(75-c)(75-d)(75-e)=11*19*11
(75-64)*(75-56)*(75-86)*(75-76)*(75-74)=11*19*-11*-1*1
therefore a+b+c+d+e=64+56+86+76+74=356

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TANVI to karthikeyank 11 years ago

a b c d e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299. then a+B+C+D+E =?

Reply Like? Yes | No

Ram 11 years ago

if a,b,c,d,e is same as a,B,C,D,E asked in the answer
2299 = (-11)*11*19*(-1)*1
75-a= -11
75-b=11
75-c=19
75-d= -1
75-e=1
a=86,b=64,c=56,d=76,e=74
a+b+c+d+e=356

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BHASKAR MANDAL 11 years ago

well done ram
keep it up
i also thought but unable to thought of the -ve

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TANVI to Inline Geek 11 years ago

a b c d e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299. then a+B+C+D+E =?

Reply Like? Yes (1) | No

himanshu wadhawan 11 years ago

a+b+c+d+e=282
a=64,b=56,c=86,d=76,e=74

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Ankit Pandey 11 years ago

sum = 356
numbers are 56, 64, 74, 76, 86

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TANVI to RAKESH 11 years ago

a b c d e are distinct numbers. if (75-a)(75-b)(75-c)(75-d)(75-e)=2299. then a+B+C+D+E =?

Reply Like? Yes (3) | No

TANVI to karthikeyank 11 years ago

You have Rs.2 with u.You have to play a game in which if u win u will get 1 Re. and if lost you will lose 1 Re.You can lose up to 3 times. But if u get 5 Rs, you are left out of the game. In how many ways is this possible?

Reply Like? Yes (2) | No

Ram 11 years ago

Answer is 111 ( if losing is up to 3 times means i can lose either 3 times max or 2 times or 1 time or no losses in a single game )
no. of losses=no. of winnings + extra 3 winnings to get 5 Rs. and leave the game
( i already have 2 Rs. so i need 3 Rs. to leave the game)
1st strategy: LLL WWW WWW ( 3 losses=3 wins so money is balanced and 3 wins= 3rs to get 5rs and leave the game) ------different ways of this case is possible =[9!/(6!*3!)] = 84
2nd strategy: LL WW WWW
----------------------different ways of this case is possible =[7!/(5!*2!)] = 21
3rd strategy: L W WWW
----------------------------different ways of this case is possible =[5!/(4!)] = 5
4th strategy: WWW (No losses)
-------------------------different ways of this case is possible =1
Total No. of Ways = 84+21+5+1
= 111

Like? Yes (5) | No

TANVI to RAKESH 11 years ago

An organization has 4 committees. Only 3 persons are members of all four committees, but every pair of committees has 4 members in common. What is the LEAST possible number of the members on any one committee?

plzzz solve

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Inline Geek 11 years ago

least possible number of employees in organization is 7 and least possible members in a committee are 5.

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Vipul 11 years ago

Pls do tell how u have solved it

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Sujithra 11 years ago

use set thoery to solve this ans will be 4

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anki singh 11 years ago

draw venn diagram...ans is 4

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