Latest Infosys Aptitude Question SOLUTION: Q. There are 2 pesons each having same amount of marbles in the beginning. after that 1 person gain 20 more from second person n he eventually lose two third of it during the play

• Placement Papers
• /
• Infosys
• /
• Logical Reasoning
• /
• General Mental Ability

Infosys Question Papers: Infosys Interview Experience(10) INFOSYS Company Profile

(#M40031211) INFOSYS Logical Reasoning question logic Keep an EYE

Q. There are 2 pesons each having same amount of marbles in the beginning. after that 1 person gain 20 more from second person n he eventually lose two third of it during the play n the second person now have 4 times marble of what 1st person is having now. find out how much marble did each had in the beginning

Asked In Infosys RagunathKC (10 years ago)

Unsolved Read Solution (5)

Is this Puzzle helpful?   (7)   (1) Submit Your Solution General Mental Ability

Read Solution (5) :

Krishna Chaitanya  (10 years ago)

Ans :100
Let two persons initially have x marbles,then after 1st play 1 person gain 20 more from second person
therefore after 1st play 1st person has x+20 and second person has x-20
after 2nd play he eventually lose two third of it during the play n the second person now have 4 times marble of what 1st person is having now
after losing 2/3(x+20) 1st person now will have 1/3(x+20)
Second person will have (x-20)+2/3(x+20)
Given second person now have 4 times marble of what 1st person is having now
therefore (x-20)+2/3(x+20)=4*1/3(x+20)
Therefore x=100
Thus initially each have 100 marbles in the beginning.

Is this solution Helpfull? Yes (47) | No (3)  

vikash kumar  (10 years ago)

ans is..each having 50-50 marbles
1st=> 50 50
2nd=> 60 40
32d=> 20 80...condition satisfy..

Is this solution Helpfull? Yes (5) | No (7)  

Swarnalatha Gadhivan  (10 years ago)

1st person 2nd person

m m
m+20 m-20 m+20)-2/3(m+20) (m-20)+2/3(m+20)


(m-20)+2/3(m+20)=4((m+20)-2/3(m+20))

m=100

Is this solution Helpfull? Yes (2) | No (2)  

madhuri gupta  (10 years ago)

qus said that in !st round A have 20 more then B...but in ur ans A have 40 more than B

Is this solution Helpfull? Yes (1) | No (1)  

saikat ghosh  (9 years ago)

initially x
after 1st round 1st person has x+10 and scnd one has x-10
after second play 1st one looses 2/3rd of his marbels . so he has now 1/3(x+10) and second one has (x-10)+2/3(x-10)
according to question
(x-10)+2/3(x-10)=4*1/3(x+10)
solving this we get x=50

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.