Latest HCL Aptitude Question SOLUTION: Q. 75 persons Major in physics, 83 major in chemistry, 10 not at major in these subjects u want to find number of students majoring in both subjects

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Q. 75 persons Major in physics, 83 major in chemistry, 10 not at major in these subjects u want to find number of students majoring in both subjects

Asked In HCL chandreyee chowdhury (10 years ago)

Solved Akanksha Mishra Read Solution (5)

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Read Solution (5) :

Akanksha Mishra  (10 years ago)

Look upon the question carefully;

Consider the number of total students = n(T) = 100
number of persons Major in physics = n(P) = 75
number of persons Major in chemistry = n(C) = 83

According to the question ;
10 not at major in these subjects = n(P'∩ C') = 10
n(P'∩ C') = n(P U C)' = 10
n(P U C)' = n(T) - n(P U C)
10 = 100 - n(P U C)
n(P U C) = 90
n(P U C) = n(P) + n(C) - n(P ∩ C)
90 = 75 + 83 - n(P ∩ C)
n(P ∩ C) = 158 - 90
n(P ∩ C) = 68

number of students majoring in both subjects WILL be 68

Is this solution Helpfull? Yes (52) | No (6)  

Avishek Pattanaik  (10 years ago)

solve it using VENN DIAGRAM
let the common part be x
*persons major in Physics only=75-x
**persons major in Chemistry only=83-x
Now,
(75-x)+x+(83-x)+10=100 [students combined as:Physics+Both+Chemistry+None]
so, x=68

Is this solution Helpfull? Yes (44) | No (3)  

PARVY GOVIL  (10 years ago)

aUb= n(A) + n(B) -n(A intersection b)
90=75+83-x
x=68

Is this solution Helpfull? Yes (16) | No (3)  

Snehashish Pal  (10 years ago)

question is wrong total students are not given

Is this solution Helpfull? Yes (11) | No (8)  

nitesh singh  (10 years ago)

a+b+c+d+d+e+f+g+g+h+i= 51,
a+b+c+d+e+f+g+h+i=45,
=> d + g = 6. d ≠ g => d, g, ≠ 3. a = 4 => d, g ≠ 4, 2.
=> a, d = 1, 5; or 5, 1.
Now h+i = 16 or 12; h+i = 16 => h, i = 7, 9; h+i = 12
=> h, i = 3, 9 => h or i = 9;
Also e + f = 11 => e + f = 2+9 or 3+8; But e, f ≠ 9
=> e, f = 3, 8.
b+c+d = 13, d, g = 1, 5. b, c = 2, 3, 6, 7.
h, i = 9 and either 3 or 7.
=> b, c = 2, 6 => d = 5 and g = 1.

Is this solution Helpfull? Yes | No (20)  

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