Latest Bank Exam Aptitude Question SOLUTION: A bag contains one rupee, fifty paise and twenty five paise coins, whose values are in the proportion 2:5:7 respectively. If the total number of coins are 400, then find the total

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A bag contains one rupee, fifty paise and twenty five paise coins, whose values are in the proportion 2:5:7 respectively. If the total number of coins are 400, then find the total value of coins.

Asked In Bank Exam nitin sharma (10 years ago)

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Karan  (10 years ago)

Total no of coins=400
The bag contains one rupee, fifty paise and twenty five paise coins, whose values are in the proportion 2:5:7 respectively and their numbers are in ratio of 2*1:5*2:7*4 or 2:10:28
so their numbers are 20,100,280 respectively.
Total value = 20+100/2 +280/4=20+50+70= Rs 140.

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sravani  (10 years ago)

total no. of coins=400
1 re no. of coins =(2/14)*400
50 p no. of coins =(5/14)*400
25 p no. of coins =(7/14)*400
Total value of coins=(2/14)*400*1+(5/14)*400*0.5+(7/14)*400*0.25
=178.57

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umang agarwal  (10 years ago)

Simply take x as the common value so 1 rupee coin value is 2x 50 paise coin value is 5x and 25 paise coin value is 7x now no. Of coin is if 1 rupee coin is 2x then 50 paise coin is 5×2 x and 25 paise coin is 7×4x.
(2+10+28)x = 400
X = 10
From that 1 rupee coin is 20.
50 paise coin = 100.
25 paise coin = 280.

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