Latest UPSC Aptitude Question SOLUTION: Q. A pujari started from home with certain number of flowers. His flowers became double with entrance of a temple, where he offered 40 flowers, then he went to a second temple. The

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Q. A pujari started from home with certain number of flowers. His flowers became double with entrance of a temple, where he offered 40 flowers, then he went to a second temple. There also his flowers doubled and he offered 40 flowers again. In the third temple also the flowers doubled and he offers 40 flowers, after which he was left with no flower.The number of flowers he bought from home were ?

Asked In UPSC (10 years ago)

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SUDHIR SHARMA  (10 years ago)

Answer is 35
Lets Stsrt with 35 Flowers , When he enter in the first temple his flowers gets
double. Now total flowers are 70 then he offers 40 flowers in the first temple.

After this he went to 2nd temple . now total flowers are (70-40)*2=60 ,
There he also offered 40 flowers , Therefore 20 flowers are remain.

In the last temple when he enters his flowers gets double ,
Now total Flowers are 20*2=40

Is this solution Helpfull? Yes (6) | No   

Snehasis  (10 years ago)

At the gate of third temple he would have 20 flowers, at the gate of second temple 30 flowers and at the gate of first temple 35 flowers ...so he bought 35 flowers from home.

Is this solution Helpfull? Yes (4) | No   

Devendra Marghade  (10 years ago)

35 Flowers
If Pujari enters with x flowers,
Flowers remaining after coming out of temple 1=2x-40
Flowers remaining after coming out of temple 2=2[2x-40]-40=4x-120
Flowers remaining after coming out of temple 3=2[4x-120]-40=0
8x-280=0,x=35

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mohit sharma  (10 years ago)

40
starts with = x
enters first temple doubles= 2*x
offer = 40
remaining= 2*x-40
enter second temples=2*x-40
doubles= 4*x-80
offers= 40
remaining= 4*x-120
enter third temple=4*x-120
doubles=8*x-240
offers= 8*x-280
finally
8*x-280=x
7*x=280
x=40

Is this solution Helpfull? Yes (1) | No (5)  

Snehasis  (10 years ago)

@mohit- it can't be 40 mohit because if he starts with 40 then he will left with 40 flowers only at last. but question says that he left with nothing so the answer should be 35. check it once...

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srinivas  (10 years ago)

ans 35
from home he bought X flowers
at first temple his flowers doubled 2X and offered 40 of them, remaining=2X-40.
at second temple his flowers doubled 2*(2X-40)=4X-80 again at second temple he gave 40 flowers then remaining=4X-80-40=4X-120.
in the same way at third temple his flowers doubled 2*(4X-120)=8X-240 and he gave 40 flowers and remaining flowers=8X-240-40=8X-280.
when he went home he has no flowers i;e zero. so
8X-280=0
X=280/8 =35

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Firdous Imam  (10 years ago)

In third temple he offered 40 n nothing left means he entered with 20 ..
In sec temple he offered 40 n 20 left ....so aftere doubling he has total 60 flowers. means he entered with 30
Now in first temple he offered 40 n left WD 30 .so total 70 flowers after doubling.. so he brought 35 from home

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BHUPENDRA DAYAL  (10 years ago)

35.
at first temple 35X2 = 70
after offering 40, now the no of flowers will be 70-40 = 30
at second temple 30X2 = 60
after offering 40, now the no of flowers will be 60-40 = 20
at third temple 20X2 = 40
after offering 40, now the no of flowers will be 40-40 = 40
Now the Pujari has no flowers in his hand..
thus the answer is 35

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Sarravanakumar  (10 years ago)

Temple 1: 35 * 2 - 40 = 30
Temple 2: 30 * 2 - 40 = 20
Temple 3: 20 * 2 - 40 = 00

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Gunasekaran M  (10 years ago)

temple1 temple2 temple3
getting 35 30 20
double 70 60 40
offer 40 40 40
balanc 30 20 0

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Vijayasri  (9 years ago)

35.. 35+35=70 then 70-40=30-> Ist temple
30+30=60 then 60-40=20 -> IInd temple
20+20=40 then 40-40=0-> III temple, so ans is 35..

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rahul  (9 years ago)

he started with 35 flowers,last he has given 40 means 20 flowers doubled,before that-2ndtime- 40,20+40
=60 half of 60 is 30,then add first 40 i,e 30+40=70 so 70/2=35

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Mithra  (9 years ago)

gate 1:2a-40
Gate 2: 4a-120
Gate 3: 8a-280 = 0, hence a = 35

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jatinder kumar  (5 years ago)

let the number of flowers he bought from home were = x
then double of flower = 2x
40 flowers offered in temple = 2x-40
again repeat = 2(2x-40)-40
again = 2(2(2x-40)-40)-40
and he left with Zero flowers
so 2(2(2x-40)-40)-40=0
by solving it
x=35

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Pankaj Kumar Khandal  (4 years ago)

2(2(2X-40)-40)-40=0

which gives you 35 .

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