Latest SSC Aptitude Question SOLUTION: the length of each of the two equal sides of an isosceles triangle is 10 cm and the included angle betweeb those two sides is 45 degree.Find the area of the triangle?

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(#M40033454) SSC Numerical Ability question Geometry Keep an EYE

the length of each of the two equal sides of an isosceles triangle is 10 cm and the included angle betweeb those two sides is 45 degree.Find the area of the triangle?

Asked In SSC Mohammad Danish Mumtaz (10 years ago)

Solved Vivek Jain Read Solution (3)

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Read Solution (3) :

Vivek Jain  (10 years ago)

Area of triangle When two sides and angle included between them is given.SAS method.
Area=1/2*a*b Sin C
=>1/2*10*10*Sin 45
=>35.4cm^2

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Vivek  (10 years ago)

For Isosceles triangle both the angles is equal. Means angle between 2 equal arm is 90 degree.
So, area= 1/2*10*10=50

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tarun gupta  (7 years ago)

Sin 45°= perpendicular/hypotenuse
1/√2 = x/10
x= 10/√2
Then
Area of triangle = 1/2*b*h
= 1/2*10*10/√2
=50/√2
=50*√2/√2*√2(both side multiply root 2)
=50*√2/2
=25√2

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