Latest Elitmus Aptitude Question SOLUTION: How many four digit can be formed using 2,3,4,5,6,7 only once divisible by 25 a 12 b 20 c 24 d 40

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(#M40033565) ELITMUS Numerical Ability question Keep an EYE

How many four digit can be formed using 2,3,4,5,6,7 only once divisible by 25
a 12
b 20
c 24
d 40

Asked In Elitmus sanjana (10 years ago)

Unsolved Read Solution (12)

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Read Solution (12) :

Saraswathy  (10 years ago)

Ans : 24

For any number to be divided by 25, it should be ended with {25,20,75,00)...
Here 0 is not in the list... so d possibilities are the numbers ended with (25 nd 75)

if v take the no. to end with 25, the remaining 2 digits can be any 2 among {3,4,6,7} . so the possibities are 4!/2= 24/2= 12

if v take the no. to end with 75, the remaining 2 digits can be any 2 among {2,3,4,6} . so the possibities are 4!/2= 24/2= 12

so 12+12=24

Is this solution Helpfull? Yes (61) | No (9)  

anujnandwana  (10 years ago)

ans is 20 as total 24 case - (3125,4375,5625,one more )

Is this solution Helpfull? Yes (5) | No (1)  

Gaurav Malhotra  (9 years ago)

ans 20.

For any number to be divided by 25, it should be ended with {25,50,75,00)
Here 0 is not in the list. so d possibilities are the numbers ended with (25 nd 75)

if v take the no. to end with 25, the remaining 2 digits can be any 2 among {3,4,6,7} . so the possibities are 4!/2= 24/2= 12

if v take the no. to end with 75, the remaining 2 digits can be any 2 among {2,3,4,6} . so the possibities are 4!/2= 24/2= 12

so 12+12=24

but 4 cases out of these 24 are such as being divided by 25 twice
these nums are 3125, 4375, 5625, 6875.

so excluding these fours , we get 24-4=20.

Is this solution Helpfull? Yes (5) | No   

priyanka dhingra  (10 years ago)

12 is d answer

Is this solution Helpfull? Yes (4) | No (10)  

deep chandra bhatt  (10 years ago)

24 ans nahi h because 4375 divisible 25 in 2times

Is this solution Helpfull? Yes (4) | No (4)  

ankit agnihotri  (10 years ago)

according to my logic ans is 12 because according to question 2,3,4,5,6,7 is to be used once ( repetition) not allowed.
note- a no. to be divisible by 25 should be ended with 25,50,75,100 but however in question we are not having zero,therefore we are restricted to 25 and 75 only.
thus,
4 positions can be filled by
3*2*2*1 = 12
proper explanation-
digits in
4th digit position = 3 or 4 or 6 (i.e 3 ways)
3rd digit position = 4 or 6( if 3 is taken to be in the 4 th place) (i.e 2 ways)
2nd digit position = 2 or 7 (i.e 2 ways)
1st digit position = 5 ( i.e 1 way)

therefore ans is 3*2*2*1 = 12

Is this solution Helpfull? Yes (1) | No (5)  

arpit jain  (10 years ago)

anuj your way of solving is right but you have forgotten 1 number 6875 so 24 - (3125, 4375, 5625, 6875)
so ans is 20

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anujnandwana  (10 years ago)

@arpit jain 6875 is not that no as 8 is not provided to us . So ,the solution you provided is wrong .

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CHAITANYA  (10 years ago)

5 multiples are 25
50---0 is not given in question so eliminated 50.
75
100---0 not given 100 eliminated.
for 5 to be the last digit ,,last but one must be either 2 or 7.
for --25
4p2=12
for --75
4p2=12
so 24.

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Mukesh Nayal  (10 years ago)

what about repetition of numbers?

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Mani kandan  (10 years ago)

Ans : 24

For any number to be divided by 25, it should be ended with {25,50,75,100)...
Here 0 is not in the list... so d possibilities are the numbers ended with (25 nd 75)

if v take the no. to end with 25, the remaining 2 digits can be any 2 among {3,4,6,7} . so the possibities are 4!/2= 24/2= 12

if v take the no. to end with 75, the remaining 2 digits can be any 2 among {2,3,4,6} . so the possibities are 4!/2= 24/2= 12

so 12+12=24

Is this solution Helpfull? Yes | No (3)  

achin dwivedi  (9 years ago)

as no should be devisible by 25 so the last two position must be 25 or 75.
when we consider _ _ 2 5 then for first two places.
select two numbers out of 4 i.e 4c2*2!(2! for arranging these).
when _ _ 7 5 then select 2 out of 4 i.e 4c2*2!(for arranging the two selected numbers).
so total ways= 4c2*2! + 4c2*2!
=6+6
=12

Is this solution Helpfull? Yes | No (2)  

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