Latest TCS Aptitude Question SOLUTION: If a traveller was offered 5 destinations in asia and 11 destinations in europe and asked to chose utmost 3 destinations in asia and overall a 11 destinations. How many ways can he

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If a traveller was offered 5 destinations in asia and 11 destinations in europe and asked to chose utmost 3 destinations in asia and overall a 11 destinations. How many ways can he travel

Asked In TCS nanda kishore (10 years ago)

Solved Debojit Pal Read Solution (15)

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Read Solution (15) :

poojitha  (10 years ago)

5c3*11c8+5c2*11c9+5c1*11c10+1=2256

Is this solution Helpfull? Yes (22) | No (1)  

Debojit Pal  (10 years ago)

He can choose atmost 3 out of 5 destinations in Asia and 11 destinations overall.
Also it is mentioned that there are 11 destinations in Europe:
No. of ways this can be done is :-
5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11= 2256 ways

Is this solution Helpfull? Yes (8) | No   

Kundan Dhande  (10 years ago)

ans is 2256
5C0*11C11 + 5c1*11c10 + 5c2*11c9 + 5c3*11c8 = 2256

Is this solution Helpfull? Yes (5) | No   

Srijita Dasgupta  (10 years ago)

if it is atmost then it will be 5c3*11c8
and if it is atleast then it will be
5c3*11c8+5c2*11c9+5c1*11c10+1=2256

Is this solution Helpfull? Yes (3) | No   

preeti jijnodiya  (10 years ago)

at least means kum se kum...
so, according to condition we have to select 11 city in which at least 3 city from asia
combinations are : 5c3*11c8 + 5c4*11c7 + 5c5*11c6
1650+1650+462 = 3762

Is this solution Helpfull? Yes (2) | No (1)  

Ramya  (10 years ago)

=5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11
=1650+550+55+1
=2256

Is this solution Helpfull? Yes (2) | No   

TANVI  (10 years ago)

5c3*11c8+5c2*11c9+5c1*11c10+5c0*11c11= 2256 ways

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Jasmeet  (10 years ago)

2256 is the ans

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B.SAIMALATHI  (10 years ago)

5C3*11C8+5C4*11C7+5C5*11C6

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Divya  (10 years ago)

atmost means max 3 destinations of asia a traveller can select and not more than tat,,so ans wil be...
5c3*11c8+5c2*11c9+5c1*11c10+1=2256

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Shruti  (10 years ago)

ans is 2256 as 5c3*11c8+5c2*11c9+5c1*11c10+1=2256
The traveller can chose utmost 3 destination from asia so he can either chose
1 station from asia and 10 stations from europe (5C1*11C10) OR
2 stations from asia and 9 stations from europe (5C2*11C9) OR
3 stations from asia and 8 station from europe (5C3*11C8)

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OUJASWAEE DAS  (10 years ago)

3762 as by combination

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miraj ansari  (10 years ago)

destination in asia=5
destination in europe=11

only 3 destination should be selected so the ways are ..
5c3*11c8 + 5c4*11c7 + 5c5*11c6 is required Ans

Is this solution Helpfull? Yes | No (1)  

prabhjot  (10 years ago)

ans is 5^7=78125.
because the last two digits should be 12,24,32,44,52. acc to divisibility rule .
so by fixing these digits at last , no. of ways for each are=5^6.
but total cases are 5,so total no of ways are 5^7.

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neha kiran mukkawar  (10 years ago)

5c0*11c11+5c1*11c10+5c2*11c9+5c3*11c8

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