Latest Capgemini Aptitude Question SOLUTION: apple+guava=orange then o+r+a+n+g+e = ?????????????????????

anyone pls tell solution to this this is one of the questions given in infosys too

answer is 30
apple
+guava
=orange
apple =1|16|16|12|5|
guava =7|21|1|22|1|
apple+guava=119046
apple+guave=orange=11+9+0+4+6=30

A=1,B =2,C=3,D=4,E=5,F=6,G=7,H=8,I=9,J=0
K=1,L=2,M=3,N=4,O=5,P=6,Q=7,R=8,S=9,T=0
U=1,V=2,W=3,X=4,Y=5,Z=6

what we do here is we assign 1,2,3..9 for the alphabets in order and by taking into account the units digit.

for example Z = 26 but it has been coded as 26%10 = 6 ( the units digit of 26 )

now add the assigned values : APPLE = A + P + P + L + E = 1 + 6 + 6 + 2 + 5 = 20 .
similarly, GUAVA = G + U + A + V + A = 7 + 1 + 1 + 2 + 1 = 12.

hence ORANGE = O+R+A+N+G+E = 5 + 8 + 1 + 4 + 7 + 5 = 30

hence value of ORANGE is 30

hope it helped!!

BANANA
+GUAVA
-------
ORANGE
-------

means A+A=E, N+V=G, A+A=N, N+U=A, A+G=R, B+_=O

So just start from last
A+A=E
"A" can have d values ranging {0,1,2,3,4,5,6,7,8,9}
first lets take A=0... A+A= 0+0=0... Again d result is 0... means E=0... So not possible for 2 alphabets to have same number...

Lets take A=1... A+A= 1+1=2... A=1, E=2,... v have to find d value for "N"...
Look A+A=N (3rd term)... A+A is already "E" (ie E=2A)... So definitely N should not be 2A... Therefore N=2A+1... There should be remainder from the 2nd term...
so N=2A+1... N=2(1)+1= 3... Assign a value for to get a remainder... Take V=7
3+7=0 carry 1... 1+A+A=3...
next N+U=A...result should be 1... 3+8=1 carry 1...
next A+G=R... 1+1+7=9... There is no carry which means B nd O ll have d same value... so not possible... So try for different values...
Note here A+G=R should produce a carry... then only v can yield B+carry=O

By trial nd error method, Again start from last... Try A=2... Its also not possible... Agan A=3... Not possible...
Now A=4... E=2A=8... N=2A+1=9...
For getting a carry If i take V=1, A+G ll not produce carry... So take V=2... N+V=G... 9+2=1 carry 1... 1+A+A=9... N+U should produce 4... 9+5=4 so U=5... next A+G = 4+1=5 not producing carry... Here 4+(>5) only yields a carry...
So v should get G value >5...
So again trail nd error method, N+V=G... Lets take V=7 ..N+V=G... 9+7=6 carry 1...
1+A+A=N... N+U=A... 9+5=4 carry 1... 1+A+G=R... 1+4+6=1 carry 1... 1+B+_=O...
Values remaining is {0,2,3}
1+0+_=1 not possible
1+2+_=3


So
B=2, A=4, N=9, A=4, N=9, A=4
G=6, U=5, A=4, V=7, A=4
O=3, R=1, A=4, N=9, G=6, E=8

O + R + A + N + G + E
3 + 1 + 4 + 9 + 6 + 8 = 31

Ans : 31

any plz solve this answer?

15+18+1+14+7+5=60

GOWTHAM your answer is wrong. Acc to you, while considering Apple, E=5 and A=1, adding last two terms(unit digits) of the numbers we should get the unit place no. for the amswer (ORANGE) which is E. And according to you, E is 6 in ORANGE which is not possible.

In Infosys question was similar to it
Apple + litchi =cherry then c+h+e+r+r+y=?

lemon+orange=apple+guava

can anyone please explain me???

plz ayone give the right ans...