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(#M40034276) CAT Numerical Ability question numbers Keep an EYE

The sum of four consecutive two digit odd numbers when divided by 10 become a prefect square. what are the consecutive numbers?

Asked In CAT SURUTHI.R (11 years ago)

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Ann Theressa  (11 years ago)

ans : 37,39,41,43

Let the numbers be (x-3),(x-1),(x+1),(x+3)

their sum = (x-3)+(x-1)+(x+1)+(x+3)
= 4x

Given 4x/10 is a perfect square
Also x is a 2 digit number

====> x = 40
so the numbers are 37,39,41,43

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SUDHIR SHARMA  (11 years ago)

37,39,41,43 wil be the numbers.
(37+39+41+43)/10 = 160/10 = 16 = (4)^2

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Nitin Jaiswal  (11 years ago)

Let the numbers be x-3,x-1,x+1,x+3.
[(x-3)+(x-1)+(x+1)+(x+3)]/10=2x/5
Since the digits are 2 digit integers this value(2x/5) can only be equal to 16 which gives x=40 and hence the numbers are 37,39,41,43.

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shubham jain  (11 years ago)

7,9,11,13
let the numbers be x,x+2,x+4 & x+6 . Where x is an odd number.
now their sum will be 4x+12, and when divided by 10. They would be (2x+6)/5, this should be perfect square. For that by putting values of x at value 7 the desired resuld is attained. that is (2*7 +6)/5.It will be 4 and it is a perfect square. so the x is 7 and the four numbers are 7,9,11,13.

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SUCHETAN SASIS  (11 years ago)

answer is 7,9,11,13
7+9+11+13=40
40/10=4
4 is a perfect square

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