Latest Elitmus Aptitude Question SOLUTION: Suppose you have a currency called miso in three denominations, 1 miso, 10misos and 50 misos. In how many ways can you pay a bill of 107 misos? Option A.17 B.16 C.18 D.15 E.19

• Placement Papers
• /
• Elitmus
• /
• Numerical Ability
• /
• Clocks and Calendars

Elitmus Question Papers:

(#M40034327) ELITMUS Numerical Ability question Keep an EYE

Suppose you have a currency called miso in three denominations, 1 miso, 10misos and 50 misos. In how many ways can you pay a bill of 107 misos?
Option
A.17
B.16
C.18
D.15
E.19

Asked In Elitmus rohit gupta (10 years ago)

Unsolved Read Solution (7)

Is this Puzzle helpful?   (16)   (0) Submit Your Solution Clocks and Calendars

Read Solution (7) :

Saraswathy  (10 years ago)

Let the number of currency 1 Miso, 10 Misos and 50 Misos be x, y and z respectively.
x+10y+50z=107

Now the possible values of z could be 0, 1 and 2.

For z=0: x+10y=107

Number of integral pairs of values of x and y that satisfy the equation:
x+10y=107 will be 11.

These values of x and y in that order are:
(7,10);(17,9);(27,8)…(107,0)

For z=1: x+10y=57

Number of integral pairs of values of x and y that satisfy the equation:
x+10y=57 will be 6.

These values of x and y in that order are:
(7,5);(17,4);(27,3);(37,2);(47,1) and (57,0)

For z=2: x+10y=7

There is only one integer value of x and y that satisfies the equation:
x+10y=7 in that order is (7,0)

Therefore total number of ways in which you can pay a bill of 107 Misos:
=11+6+1= 18

Ans : (C)

Is this solution Helpfull? Yes (94) | No (1)  

gaurav arora  (10 years ago)

18 is answer
1.)1+1+1+......107 times=107
2.)10+1+1......97 times=107
3.)10+10+1+1......87 times=107
....
........
11.)10+10+.....10 times + 1+1+...7 times=107
12.)50+1+1+....57 times=107
13.)50+10+1+1....47 times=107
....
.......
17.)50+10+10+...5 times + 1+1+....7 times=107
18.)50+50+1+1....7 times=107
so 18 ways

Is this solution Helpfull? Yes (7) | No   

anujnandwana  (10 years ago)

ans is c
18

Is this solution Helpfull? Yes (2) | No   

shree  (10 years ago)

A)17 is right answer because
1+1+1+...........=107
10+1+1...........=107
....
........
10+10+..........=107
50+10+1+1.......=107
50+50+1+1.......=107
so 17 ways

Is this solution Helpfull? Yes | No (7)  

sundar  (8 years ago)

no of ways=maximum usage of each miso/2*minimum usage of each miso=(107 of 1 miso*10 of 10 miso*2 of 50 miso)/7 of 1 miso*1 0f 10 miso=2140/2*7=2140/14=15

Is this solution Helpfull? Yes | No (1)  

utkarsh singh  (8 years ago)

c
obvious one can easily check.

Is this solution Helpfull? Yes | No   

Digesh Singh Bisht  (1 year ago)

ans is 18

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.