Latest CAT Aptitude Question SOLUTION: Two pipes a and b can fill a tank in 6hrs and 4 hrs respectively. if they are opened on alternate hour and if pipe a is opened first in how many hours, the tank shall be full?

• Placement Papers
• /
• CAT
• /
• Numerical Ability
• /
• Time and Work

CAT Question Papers:

(#M40034678) CAT Numerical Ability question pipes and cisterns Keep an EYE

Two pipes a and b can fill a tank in 6hrs and 4 hrs respectively. if they are opened on alternate hour and if pipe a is opened first in how many hours, the tank shall be full?

Asked In CAT ramakrishna (10 years ago)

Solved Saraswathy Read Solution (4)

Is this Puzzle helpful?   (12)   (1) Submit Your Solution Time and Work

Read Solution (4) :

Saraswathy  (10 years ago)

a's 1 hr work = 1/6
b's 1 hr work = 1/4

in 2 hrs a ll fill 2 * 1/6 = 1/3
in 2 hrs b ll fill 2 * 1/4 = 1/2

so 1/3 + 1/2 = 5/6
Remaining part yet to be filled = 1 - 5/6 = 1/6

So 2 + 2 = 4 hrs [A, B, A, B]
Next turn is A's...
A ll fill 1/6 part in 1hr...

So 2 + 2 + 1 = 5hrs

Ans : 5 hrs

Is this solution Helpfull? Yes (8) | No   

sravani  (9 years ago)

1st hr tank is filled by a i.,e 1/6
2nd hr tank is filled by b i.,e 1/4
for 2hrs 1/6 + 1/4 = 5/12
4hrs =2(5/12)=10/12
5 hrs=10/12 + 1/6=12/12=1
so,within 5Hrs tank will be filled.

Is this solution Helpfull? Yes (2) | No   

ram kiran  (10 years ago)

(A+B)'s 2 hour's work when opened =1/6+1/4=5/12
(A+B)′s 4 hour's work=(5/12)∗2=5/6
Remaining work = 1−(5/6)=1/6
Now, its A turn in 5th hour
1/6 work will be done by A in 1 hour
Total time = 4+1=5hours

Is this solution Helpfull? Yes (1) | No   

VENKATESHBABU JN  (5 years ago)

Lcm of 6 and 4 is 12( total capacity of tank )
So 1st hr...2( A's one hr work)
2nd hr..3(B's one hr work )
2
3
2
So total 5 hrs

Is this solution Helpfull? Yes | No   

Please Login to Read Solution.