Latest A website Aptitude Question SOLUTION: At 10 a.m two trains started traveling toward each other from stations 287 miles apart.they passed each other at 1.30p.m the same day.If the average speed of the faster train excee

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(#M40034683) A WEBSITE Numerical Ability question train Keep an EYE

At 10 a.m two trains started traveling toward each other from stations 287 miles apart.they passed each other at 1.30p.m the same day.If the average speed of the faster train exceeded the average speed of the slower train by 6 miles per hour,find speed of the faster train in miles per hour?

Asked In A website Ramya (10 years ago)

Solved Ann Theressa Read Solution (1)

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Read Solution (1) :

Ann Theressa  (10 years ago)

44 miles per hour

Let the speed of faster train be x
Speed of slower train = (x-6)

Time taken to cross each other = 3hours 30 min = 7/2 hours
Distance travelled = 287
Relative speed = x+x-6 = 2x-6

Speed = diatance / time
2x - 6 = 287/7/2
=82
2x = 88
x = 44

Speed = 44 miles per hour

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