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(#M40034809) CTS Numerical Ability question Maths Keep an EYE

A Product is supported each week by the same three customer service Representatives (CSR's). Last month the first CSR took 450 calls, the second took 350 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three CSR's each increase their work proportionately, how many more calls will the first CSR take this month than last month? Explain in steps

Asked In CTS Deepika KV (11 years ago)

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Saraswathy  (11 years ago)

Last month ratio C1 : C2 : C3 = 45 : 35 : 30 => 9 : 7 : 6

This month total calls = 1500
9x + 7x + 6x = 1500
x= 1500/22 = 750/11

C1 ratio = 9 * 750/11 = 613.6 => 614 approximately
C2 ratio = 7 * 750/11 = 477.2
C3 ratio = 6 * 750/11 = 409
Calls first CSR ll take more than last month = 614 - 450 = 164

Ans : 164

Is this solution Helpfull? Yes (56) | No   

SRI VIKRAM SUNDAR  (10 years ago)

Calls taken by first csr1 = 450, csr2 = 350, csr3=300
so their ratio is = 450:350:300
==> 9:7:6

Total calls for the next month ==>1500

9x+7x+6x = 1500
22x=1500
x=1500/22 ==> 750/11

first CSR1 ratio == 9*(750/11) ==> 613.6 ==>614

First month csr1 calls = 450

So increase in calls for the coming month = 614 - 450 ==> 164

Is this solution Helpfull? Yes (2) | No   

Raja  (11 years ago)

product supported by each is same
so,
3 mp=1500
each mp is 500
calls take increase by first csr is
500-450=50
Ans is ->50

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