Latest Miscellaneous Company Exam Aptitude Question SOLUTION: There are 5 persons, they have assigned their designations based on their age, they are given 100 gold coins, the person with highest designation distributes coins among themselves

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(#M40034929) MISCELLANEOUS COMPAN Numerical Ability question coins Keep an EYE

There are 5 persons, they have assigned their designations based on their age, they are given 100 gold coins, the person with highest designation distributes coins among themselves. After distribution all of them have to vote against or vote for the person who distributes the coins based on whether they have satisfied with the coins they got. If 3 or more votes r against him (person who distributes the coins votes for himself) they that person would be killed, and the person with 2nd highest designation will again redistributes the coins, so on. So the person with highest designation has to make sure that he will survive and he will get more coins than anybody else, so how will he distributes the coins?

Asked In Miscellaneous Company Exam Rekha S (10 years ago)

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Ann Theressa  (10 years ago)

Working backwards
Let us consider D and E are left(all others are killed)
So D will have to distribute the coins.D will divide the coins as 100 and 0. ie 100 coins for himself and 0 coins for E, because anyways he will get 1 out of 2 votes (he will vote for himself)

Now if C distributes the coins he will take 99 for himself and give 1 to E.E will vote for C because if he doesn't , C would get killed and D would take the 100 coins for himself and E won't get any.So C will get 2 out of 3 votes

When B distributes the coins he will take 99 coins and give 1 to D.B and D will vote for this.

So A will distribute the coins as 98,0,1,0,1
ie 98 for himself
1 for C and 1 for E
C and E will vote for this as otherwise if B distributes, they will get nothing.
So A get 3 out of 5 votes

Is this solution Helpfull? Yes (4) | No (2)  

Ann Theressa  (10 years ago)

Let the 5 persons be A,B,C,D and E.
A with the highest designation,B second, C third, D fourth and E with lowest designation.

The person with highest designation (ie A)will take 98 coins and give one coin to C and one coin to E.

Is this solution Helpfull? Yes | No (1)  

Rekha S  (10 years ago)

plz xplain me in details

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Suman  (10 years ago)

Pls check

http://www.mathsisfun.com/puzzles/5-pirates-solution.html

Also read
To understand the answer, we need to reduce this problem to only 2 pirates. So what happens if there are only 2 pirates. Pirate 2 can easily propose that he gets all the 100 gold coins. Since he constitutes 50% of the pirates, the proposal has to be accepted leaving Pirate 1 with nothing.

Now let’s look at 3 pirates situation, Pirate 3 knows that if his proposal does not get accepted, then pirate 2 will get all the gold and pirate 1 will get nothing. So he decides to bribe pirate 1 with one gold coin. Pirate 1 knows that one gold coin is better than nothing so he has to back pirate 3. Pirate 3 proposes {pirate 1, pirate 2, pirate 3} {1, 0, 99}. Since pirate 1 and 3 will vote for it, it will be accepted.

If there are 4 pirates, pirate 4 needs to get one more pirate to vote for his proposal. Pirate 4 realizes that if he dies, pirate 2 will get nothing (according to the proposal with 3 pirates) so he can easily bribe pirate 2 with one gold coin to get his vote. So the distribution will be {0, 1, 0, 99}.

Smart right? Now can you figure out the distribution with 5 pirates? Let’s see. Pirate 5 needs 2 votes and he knows that if he dies, pirate 1 and 3 will get nothing. He can easily bribe pirates 1 and 3 with one gold coin each to get their vote. In the end, he proposes {1, 0, 1, 0, 98}. This proposal will get accepted and provide the maximum amount of gold to pirate 5.

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mahesh  (10 years ago)

answer is 24+19+19+19+19 all will vote to A who earns 24 and distributed 19 to each
and according to question every one should be alive and everyone should get some coins definetly(>0).

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mahesh godbole  (8 years ago)

ABCDE will get 4+10+18+28+40=100

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